Answer:
No it cannot be concluded.
Step-by-step explanation:
The probability of getting the disease in the first attempt is 50%
The probability of getting the disease in the second attempt is 50%
Thus the probability of getting the disease in either of the turns is 50%+50%=100% (which may seem to be true)
BUT
The probability of not getting the disease in the first attempt is 50%
The probability of not getting the disease in the second attempt is 50%
Thus the probability of not getting the disease in either of the turns is 50%+50%=100% (which is also true for this case)
Thus the probability of getting the disease in either of the 2 contacts is still 50%
Answer:
One possible answer would be they sold 80 student tickets and 30 adult tickets
Step-by-step explanation:
set up two inequalities, one to show number of tickets that can be sold, and the other is how much money they need to make
5x+10y G than or = 700
x+y L than or = 110
The first inequality shows that each student (x) ticket sells for $5, and each adult (y) ticket sells for $10, and the amound has to be greater or equal to 700.
The second inequality shows that both student and adult tickets sold have to be less than or equal to 110.
First find either x or y, in this case finding y was easier
y is g than or = to 30
This means that they sold at least 30 adult tickets= $300
With y, plug into the inequality x+y L than or = to 110 to find x
x is less than or = to 80
This means that they sold at most 80 student tickets = $400
Hope this helps!
