Answer:

The problem:
Find
if
,
, and
.
Step-by-step explanation:


Replace
in
with
since we are asked to find
:
![\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
![\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
This implies that 
Let's check:



![\sqrt[3]{(x+1)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28x%2B1%29%2B2%7D)
![\sqrt[3]{x+1+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D)
which is the required result for
.
Answer:
2x^2
Step-by-step explanation:
combine like terms, and do the subtraction!
Answer:
<u><em>30cm</em></u>
Step-by-step explanation:
Given data
When are square is cut diagonally into two parts
The resulting shape is a triangle
hence the area of the square = 50+50 = 100cm^2
The length of each side of the square = √100= 10cm
likewise the diagonal of the square = 10cm
<u><em>Hence the perimeter of the resulting triangle= 10+10+10= 30cm</em></u>
Answer:
the answer is C (280 square feet)
Step-by-step explanation:
First, cut the lawn so that it becomes two shapes: a rectangle, and a triangle. Solve for both areas.
A(r) = lw
A(r) = (14)(16)
A(r) = 224 square feet
A(t) = bh/2
A(t) = (8)(14) / 2
A(t) = 112 / 2
A(t) = 56 square feet
Add the two areas:
A(r) + A(t) = Area of lawn
224 square feet + 56 square feet = 280 square feet.
The price that does not belong is 16,18.40. You do this by finding the percent gratuity, which is 15%. All the other values have 15% gratuity except the $16.