100 ---> 96 is -4
96 ---> 104 is +8
104 ---> 88 is -16
88 ---> 120 is +32
120 ---> 56 is -64
So first we go down by 4, then up by 8, then down 16, then up 32, then finally down 64.
The pattern of numbers is: -4, +8, -16, +32, -64
Notice it's the powers of 2:
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64
each term doubles. Also each term alternates in sign. One is positive, then the next is negative and so on.
The last difference is -64, which doubles to -128. Change the sign to positive to get +128
Add 128 to the last term of 56 to get
128+56 = 184
Therefore, the final answer is 184
Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
Do you mean an isosceles triangle? If you do then the answer is yes because two of the angles cannot be more that 90o. If they are the sum of the angles are going to be more than 180.
For example, if both angles in the isosceles triangles are 100 then the two angles will add up to 100 + 100 = 200 degrees. No triangle has 200 degrees in it.
Well how about 90.? Could two angles in a triangle have 90 each?
No because 90 + 90 = 180. There's no room for another angle.
So two angles of an isosceles triangle must be acute.
If this is not what you mean, please leave a not.
F(x) = a(x-h)²<span> + k
</span><span><u>Given that the vertex is (-3 -6):</u>
</span>f(x) = a(x + 3)² -6
<span>
<u>Given that it passes through (0.0), find a:</u>
a(0 + 3)</span>² - 6 = 0
<span>
9a - 6 = 0
9a = 6
a = 6/9 =2/3
<u>So the equation is :</u>
</span>f(x) = 2/3(x + 3)² -6
<span>
<u>Write the equation in standard form:</u>
</span>f(x) = 2/3(x² + 6x + 9) - 6
f(x) = 2/3x² + 4x + 6 - 6
f(x) = 2/3x² + 4x
<span>
Answer: </span>f(x) = 2/3x² + 4x<span>
</span>
Using geometric sequence form, we can rewrite it as:
Since r < 1, there exists a limit, and thus, it is said to converge.
Since the ratio is still positive, as n tends towards infinity, the graph of the sequence will never go below the horizontal. Thus, we say that the limit of the function is zero, which means that as we increase the size of n, eventually after the infinite-th time, it will hit zero.
