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4 years ago

What is a liquid homogeneous mixture called in which the solute is dissolved and distributed evenly within the solvent?

Chemistry

2 answers:

Colt1911 [192]4 years ago

8 0

Answer:

Solution

Explanation;

The homogeneous liquid in which solute is dissolved evenly with in solvent is called solution.

im single so if you see this then leave a comment :D

natka813 [3]4 years ago

5 0

Answer:

Solution

Explanation:

Solution:

The homogeneous liquid in which solute is dissolved evenly with in solvent is called solution.

All other options are incorrect because,

Colloid:

Colloid is solution in which particle size is 1- 1000 nm in diameter and still need to distribute evenly through out the solution.

Compound:

A compound is a chemical substance made up of atoms of different elements.

The atoms of different elements combine in a fixed proportion. A compound may be liquid, solid or gas.

Emulsion:

It is the mixture of two or more liquids which are immiscible.

The process of mixing both liquid is called emulsification.

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During which stage of meiosis is the diploid number of chromosomes reduced to haploid

Genrish500 [490]

Meiosis 1 is the reductional division ! so after telophase 1 , cytokinesis takes place and two haploid cells are formed !

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4 years ago

If 0.15 mol of I2 vapor can effuses through an opening in a heated vessel in 36 sec, how long will it take 0.15 mol of Cl2 to ef

marysya [2.9K]

<u>Answer:</u> The amount of time required by chlorine gas to effuse is 19 seconds.

<u>Explanation:</u>

Rate of a gas is defined as the amount of gas displaced in a given amount of time.

$\text{Rate}=\frac{n}{t}$

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

So,

$\left(\frac{\frac{n_{Cl_2}}{t_{Cl_2}}}{\frac{n_{I_2}}{t_{I_2}}}\right)=\sqrt{\frac{M_{I_2}}{M_{Cl_2}}}$

We are given:

Moles of iodine gas = 0.15 moles

Moles of chlorine gas = 0.15 moles

Time taken by iodine gas = 36 seconds

Molar mass of iodine gas = 254 g/mol

Molar mass of chlorine gas = 71 g/mol

Putting values in above equation, we get:

$\left(\frac{\frac{0.15}{t_{Cl_2}}}{\frac{0.15}{36}}\right)=\sqrt{\frac{254}{71}}\\\\\frac{0.15}{t_{Cl_2}}\times \frac{36}{0.15}=1.89\\\\t=19s$

Hence, the amount of time required by chlorine gas to effuse is 19 seconds.

6 0

3 years ago

Write an equation that shows the formation of the iodide ion from a neutral iodine atom.

Dennis_Churaev [7]

In its elemental form, Iodine is a diatomic molecule in the gas phase. In the periodic table, Iodine is just right beside Xenon which is a stable element because it has no extra electrons. Thus, to conform to stability, Iodine must have to gain one more electron. That's why in its ionic form, its formula is I⁻. The reaction would be

I₂ → 2 I⁻

To achieve the Law of Definite Proportions from Dalton's Atomic Theory, we must balance the reaction. So in every neutral Iodine atom, 2 Iodide ions are formed.

5 0

4 years ago

Read 2 more answers

How can I find the atomic number and atomic mass of an element?

Zepler [3.9K]

Located on the element smallest number at the bottom and the corner

6 0

3 years ago

Read 2 more answers

b) If 35 grams of copper (II) chloride react with 20 grams of sodium nitrate, how much sodium chloride can be formed? what is th

charle [14.2K]

Answer:

CuCl₂ is the excessive reactant and NaNO₃ the limiting reactant, 13.7g of NaCl can be formed.

Explanation:

Based on the reaction:

CuCl₂ + 2NaNO₃ → 2NaCl + Cu(NO₃)₂

To solve the problem we must convert the mass of each reactant in order to find limiting reactant as follows:

<em>Moles CuCl₂ -Molar mass: 134.45g/mol-:</em>

35g * (1mol / 134.45g) = 0.26 moles

<em>Moles NaNO₃ -Molar mass: 84.99g/mol-:</em>

20g * (1mol / 84.99g) = 0.235 moles

For a complete reaction of 0.235 moles of NaNO₃ there are required:

0.235 moles NaNO₃ * (1 mol CuCl₂ / 2 mol NaNO₃) = 0.118 moles CuCl₂

As there are 0.26 moles CuCl₂,

<h3>CuCl₂ is the excessive reactant and NaNO₃ the limiting reactant</h3><h3 />

As 2 moles of NaNO₃ produce 2 moles of NaCl, he moles of NaCl produced are: 0.235 moles NaCl. The mass is:

<em>Mass NaCl -Molar mass: 58.44g/mol-:</em>

0.235 moles NaCl * (58.44g / mol) =

<h3>13.7g of NaCl can be formed</h3>

7 0

3 years ago