1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Evgesh-ka [11]
3 years ago
5

If 0.15 mol of I2 vapor can effuses through an opening in a heated vessel in 36 sec, how long will it take 0.15 mol of Cl2 to ef

fuse under the same conditions?
Chemistry
1 answer:
marysya [2.9K]3 years ago
6 0

<u>Answer:</u> The amount of time required by chlorine gas to effuse is 19 seconds.

<u>Explanation:</u>

Rate of a gas is defined as the amount of gas displaced in a given amount of time.

\text{Rate}=\frac{n}{t}

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

So,

\left(\frac{\frac{n_{Cl_2}}{t_{Cl_2}}}{\frac{n_{I_2}}{t_{I_2}}}\right)=\sqrt{\frac{M_{I_2}}{M_{Cl_2}}}

We are given:

Moles of iodine gas = 0.15 moles

Moles of chlorine gas = 0.15 moles

Time taken by iodine gas = 36 seconds

Molar mass of iodine gas = 254 g/mol

Molar mass of chlorine gas = 71 g/mol

Putting values in above equation, we get:

\left(\frac{\frac{0.15}{t_{Cl_2}}}{\frac{0.15}{36}}\right)=\sqrt{\frac{254}{71}}\\\\\frac{0.15}{t_{Cl_2}}\times \frac{36}{0.15}=1.89\\\\t=19s

Hence, the amount of time required by chlorine gas to effuse is 19 seconds.

You might be interested in
Which atom would form a cation?<br> F<br> Na<br> N<br> P
sineoko [7]

Answer:

I believe Na

Explanation:

Copper, because it is the only metal out of all of them.

Therefore copper is the only element that can loose electrons to have a positive charge, it is the most likely to become a cation.

5 0
3 years ago
Hydrogen bonds within liquid water are attractions between protons and hydroxide ions. are dipole-dipole attractions. are ion-in
barxatty [35]

Answer:

true because the bonds cannot be broken down

6 0
2 years ago
A county creates an park to protect a forest.
Hatshy [7]
Great for the ecosystem
3 0
3 years ago
If you want to use a serial dilution to make a 1/50 dilution. The first dilution you make is a 1/5 dilution with a total volume
fomenos

Answer:

c.

Explanation:

A serial dilution is a dilution that is made fractionated. The stock solution is diluted, then this now solution is diluted, and then successively. The final dilution is the multiplication of the steps dilutions.

The representation of the dilution is v/v (volume per volume) indicates how much of the stock solution is in the total volume of the solution. So 1/5 indicates 1 mL to 5 mL of the solution. If the final volume must be 1 mL, then the stock solution must be 0.2 mL (0.2/1 = 1/5), and the volume of the solvent is 1 mL - 0.2 = 0.8 mL.

The second solution is done with a dilution of 1/10 or 1 mL of the first solution in 10 mL of the total solution. Because the solution has 1 mL, then the volume of the first solution must be 0.1 mL (0.1/1 = 1/10), and the volume of the solvent that must be added is 1 mL - 0.1 mL = 0.9 mL.

5 0
3 years ago
For the following reaction, 33.7 grams of bromine are allowed to react with 13.0 grams of chlorine gas.
Ira Lisetskai [31]

Explanation:

The reaction is given as;

Br2(g) + Cl2(g) ----> 2BrCl(g)

From the equation;

1 mol of Br2 reacts with 1 mol of Cl2

Converting the masses given to moles, using the formular;

Number of moles = Mass / Molar mass

Br2;

Number of moles = 33.7 g / 159.808 g/mol = 0.21088 mol

Cl2;

Number of moles = 13.0 g / 70.906 g/mol = 0.18334 mol

From the values;

0.18334 mol of Cl2 would react with 0.18334 mol of Br2 with an excess of 0.02754 mol of Br2

<em>What is the maximum amount of bromine monochloride that can be formed? __________grams</em>

<em />

1 mol of Cl2 produces 2 mol of Bromine Monochloride

0.18334 mol of Cl2 would produce x

Solving for x;

x = 0.18334 * 2 = 0.36668 mol

Converting to mass;

Mass = Number of moles * Molar mass = 0.36668 mol * 115.357 g/mol

Mass = 42.299 g

<em />

<em>What is the FORMULA for the limiting reagent?</em>

<em />

The limiting reagent is Cl2 as it determines the amount of product formed. The moment the reaction uses up Cl2, the reaction stops.

<em>What amount of the excess reagent remains after the reaction is complete? __________grams</em>

The excess reagent is Br2

The number of moles left is;

0.02754 mol of Br2

Converting to mass;

Mass = Number of moles * Molar mass = 0.02754 mol  * 159.808 g/mol

Mass = 4.401 g

7 0
2 years ago
Other questions:
  • How can we find the volume of this fish tank? Please I needed but Good
    10·1 answer
  • If 20 ml of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm what's the be
    12·1 answer
  • How can you determine the quantities of reactants and products in a chemical reaction
    15·1 answer
  • Which two tools are used to measure humidity?
    13·2 answers
  • What are areas of the workforce can science be applied to
    7·1 answer
  • What is the change in enthalpy when 180 g of water vapor condenses at 100°C? (AH, = 40.67 kJ/mol)
    6·1 answer
  • What do the elements within a "period" have in common? (pick one)
    7·2 answers
  • Which is not true of atoms?
    14·1 answer
  • (08.02 MC)
    15·1 answer
  • A student prepares a solution of Potassium Nitrate (KNO3) containing 95g at 40 C. This solution is -
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!