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Kitty [74]
4 years ago
11

I'm not sure how to solve for x

Mathematics
2 answers:
garik1379 [7]4 years ago
5 0
4x(x-2)=(2x+1)(2x-3)
in the first expression distribute the 4x, in the second expression FOIL

4x²-8x=4x²-6x+2x-3
combine like terms

4x²-8x=4x²-4x-3
subtract 4x² from each side 

-8x=-4x-3
add 8x to each side 

0=4x-3
add 3 to each side 

3=4x
divide by 4 on each side 

x= 3/4 or 0.75
romanna [79]4 years ago
4 0
4x(x-2) = (2x+1) (2x-3)
Distributive property: 4x^2 - 8x = 4x^2 - 6x + 2x -3
subtract 4x^2 both side : -8x=-4x-3
                                         +4x      +4x
                                         -4x=-3
x= 3/4
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1. What is the difference between the altitude rule and the leg rule?
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Answer:

The altitude to the hypotenuse of a right triangle forms two triangles that are similar to each other and to the original triangle

The Leg Rule (or Leg geometric mean theorem) relates the length of each leg of a right triangle with the segments projected by them on the hypotenuse.

Step-by-step explanation:

The altitude to the hypotenuse of a right triangle is the mean proportional between the segments into which it divides the hypotenuse. Notice the triangle used with this rule. The leg of a right triangle is the mean proportional between the hypotenuse and the projection of the leg on the hypotenuse.

6 0
2 years ago
12. (05.02 LC) Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = 7 over q and
meriva

Answer:

sec~y=\frac{q}{r}

Step-by-step explanation:

tan ~y=\frac{7}{r} \\\\\frac{sin~y}{cos~y} =\frac{7}{r} \\\\sin~y=\frac{7}{r} cos~y\\sin ~y=\frac{7}{q} \\\frac{7}{q} =\frac{7}{r} cos~y\\sec~y=\frac{7}{r}  \times \frac{q}{7} =\frac{q}{r}

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3 years ago
Solve the equation a + b - c = 180 for a. *​
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Answer:

a = 180 - b + c

Step-by-step explanation:

a + b - c = 180

Move b by subtracting b from both sides.

a - c = 180 - b

Move c by adding c to both sides.

a = 180 - b + c

Therefore a equals 180 - b + c.

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3 years ago
On a standard reticulocyte preparation with new methylene blue, there are 100 cells counted with blue-stained granulofilamentous
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Answer:

0.322 × 10¹² /L

Step-by-step explanation:

Data provided in the question:

Number of cells counted with blue-stained granulofilamentous material

i.e number of RET = 100

The red blood cells count = 3.22 × 10¹² /L

Hematocrit = 30%

Now,

RET% = [ [ Number of RET ] ÷ 1000 RBCs ] × 100%

= [ 100 ÷ 1000 ] × 100%

= 0.1 × 100%

= 10%

also,

Absolute reticulocyte count = ( %RET × RBC count ) ÷ 100

= [ 10 × 3.22 × 10¹² /L ] ÷ 100

= 0.322 × 10¹² /L

8 0
3 years ago
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