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3 years ago

Which expression is equivalent to (3x^2+4x-7)(x-2)

Mathematics

2 answers:

poizon [28]3 years ago

7 0

Answer:

B. (3x^2+4x-7)+2(3x^2+4x-7) Is your answer

Step-by-step explanation:

Lesechka [4]3 years ago

4 0

Answer:

I got B on apex

Step-by-step explanation:

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Look at the picture and solve the equations

ch4aika [34]

Answer:

1. a= 7, one solution

2. x=x, infinitely solutions

3. y=3, one solution

4. x=6, one solution

5. no solution

6. k = 2, one solution

Step-by-step explanation:

7a - 6 = 43

7a = 49

one solution

a = 7

3x + 4 = 3x + 4

3x = 3x

x = x

infinitely solutions

4(2y - 4) = 5y + 2

8y - 16 = 5y + 2

3y -16 = 2

3y = 18

one solution

y= 6

multiply 2 on both sides

5x + 6 = x + 30

4x = 24

one solution

x = 6

4e - 19 = 4(e-4)

4e - 19 = 4e -16

-19 ≠ -16

no solution

10k - 2(k+3) = 10

10k -2k - 6 = 10

8k - 6 = 10

8k = 16

one solution

k = 2

6 0

2 years ago

You randomly select k integers between 1 and 100, inclusive. What is the smallest k that guarantees that at least one pair of th

vredina [299]

Answer:

Step-by-step explanation:

The possible components to sum up to 101 can only be divided into 2 groups, 1 is larger than 50 and the other is less than or equals to 50

For example

50 + 51 = 101

52 + 49 = 101

60 + 41 = 101

...

99 + 2 = 101

100 + 1 = 101

Therefore, the worst case scenario is to pick all numbers from only 1 group, either all number less than or equal to 50, which there are 50 of them from 1 to 50, or greater than 50, which there are 50 of them from 51 to 100.

So k has to be at least 51 to guarantee that at least one pair of the selected integers will sum to 101

6 0

3 years ago

A blueberry pie is shot out of a pie cannon from a height of 6m and with a velocity of 60 m/s. How many seconds will pass before

sveta [45]

Answer: 1.106 s

Step-by-step explanation:

This situation is related to projectile motion and one the equation that models the height of the blueberry pie in time is:

$y=y_{o}+V_{o}sin(\theta) t-\frac{1}{2}gt^{2}$

Where:

$y=0 m$ is the blueberry pie final height (when it hits the ground)

$y_{o}=6 m$ is the blueberry pie initial height

$V_{o}=60 m/s$ is the blueberry pie initial velocity

$\theta=0 \°$ is the angle, assuming the pie was shot horizontally

$t$ is the time

$g=9.8 m/s^{2}$ is the acceleration due gravity

Rewriting the equation:

$0=y_{o}-\frac{1}{2}gt^{2}$

Isolating $t$ :

$t=\sqrt{\frac{2y_{o}}{g}}$

$t=\sqrt{\frac{2(6 m)}{9.8 m/s^{2}}}$

Finally:

$t=1.106 s$

5 0

2 years ago

WILL MARK U BRAINLIEST PLEASE HELP

natulia [17]

The height of the cone is 8.59

6 0

2 years ago

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Which statement is true? A. In any right triangle, the sine of one acute angle is equal to the cosine of the other acute angle.

mr Goodwill [35]

That would be choice 2. One acute angle is the complement of the other

eg in a 90-60-30 triangle sine 30 = cos 60

8 0

2 years ago

Read 2 more answers