Answer:
34 cm
Step-by-step explanation:
The actual question is How many inches of ribbon Peter will need to make the "X".
Using the Pythagorean theorem, the length of the diagonal of a square with 12 cm sides is:

Since the "X" requires two diagonals, the length of ribbon required is:

The length required, rounded to the nearest centimeter, is 34 cm.
Answer:
<h2>It is 159.1 in^2 </h2>
Step-by-step explanation:
I hope that is useful for you
Answer:
The equation is y = (3/7)x - 7.
Step-by-step explanation:
Given that the point slope form of an equation is y = mx + b where m represents the gradient and b is the y-intercept. Then, you have to substitute the following values into the equation :






Hello!
First of all, we can subtract the stretching time. This gives us 20. If we divide by the four laps we get 5 minutes per lap.
Now, one lap is 400 meters (most tracks are), which is equal to 15,748.03 inches. This means it takes her five minutes to walk 15,748.03 inches. This is also equal to 300 seconds, so it takes her 300 minutes per 15,748.03 inches.
But if we round our big inches number to the nearest ten thousandth, we get 16,000, so in a simpler form her pace is 300/16,000. But we need to find in per second. Therefore we will divide by 300 to find how many inches she walks per second. This means she walks about 53.33 inches per second.
I hope this helps!