Using two step equation how do I solve 16= (x + 3)^2

A standard roulette wheel with slots labeled 0, 00, 1, 2, 3, … , 36 is spun 60 times. Of these spins, the number 7 is spun 7 tim

WARRIOR [948]

Since the p-value of the test is of 0.00001 < 0.01, these results have statistical significance.

<h3>What is the relation between the p-value and the conclusion of the test hypothesis?</h3>

Depends on if the p-value is less or more than the significance level:

If it is more, the null hypothesis is not rejected, which means that the results do not have statistical significance.

If it is less, it is rejected, which means that the results have statistical significance.

In this problem, the probability is the p-value, hence since the p-value of the test is of 0.00001 < 0.01, these results have statistical significance.

More can be learned about p-values at brainly.com/question/13873630

#SPJ1

6 0

2 years ago

Solve each inequality. Graph the solution on a on a number line. p-7/12>3/10

Dovator [93]

Answer:

so to solve an inequality you just treat the inequaltity sign like an equals sign except if you multiply by negative 1 you flip the direction of the sign.

p-7/12>3/10

add 7/12 to both sides

p>7/12+3/10

p>35/60+18/60

p>53/60

so if you had to graph this on a number line you would have an open circle on 53/60 and an arrow coming off pointing to the right

Step-by-step explanation:

3 0

2 years ago

N-7<15 then graph on number line

lidiya [134]

Answer:

n<22

Step-by-step explanation: That is the best i can do it

7 0

3 years ago

What is the factorization of the polynomial below: -x^2-15x-54 thxxx <3

Klio2033 [76]

This might be the answer you’re looking for (−x−6)(x+9)

3 0

3 years ago

Please someone help me with the question

Yuki888 [10]

Answer:

$\displaystyle \frac{d}{dx}[e^{2x}] = 2e^{2x}$

$\displaystyle \frac{d}{dx}[e^{3x}] = 3e^{3x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Exponential Rule [Multiplying]: $\displaystyle b^m \cdot b^n = b^{m + n}$

Calculus

Derivatives

Derivative Notation

eˣ Derivative: $\displaystyle \frac{d}{dx}[e^x] = e^x$

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{d}{dx}[e^{2x}] = \frac{d}{dx}[e^x \cdot e^x]$

$\displaystyle \frac{d}{dx}[e^{3x}] = \frac{d}{dx}[e^x \cdot e^{2x}]$

Step 2: Differentiate

$\displaystyle \frac{d}{dx}[e^{2x}]$

[Derivative] Product Rule: $\displaystyle \frac{d}{dx}[e^{2x}] = \frac{d}{dx}[e^x]e^x + e^x\frac{d}{dx}[e^x]$
[Derivative] eˣ Derivative: $\displaystyle \frac{d}{dx}[e^{2x}] = e^x \cdot e^x + e^x \cdot e^x$
[Derivative] Multiply [Exponential Rule - Multiplying]: $\displaystyle \frac{d}{dx}[e^{2x}] = e^{2x} + e^{2x}$
[Derivative] Combine like terms [Addition]: $\displaystyle \frac{d}{dx}[e^{2x}] = 2e^{2x}$

$\displaystyle \frac{d}{dx}[e^{3x}]$

[Derivative] Product Rule: $\displaystyle \frac{d}{dx}[e^{3x}] = \frac{d}{dx}[e^x]e^{2x} + e^x\frac{d}{dx}[e^{2x}]$
[Derivative] eˣ Derivatives: $\displaystyle \frac{d}{dx}[e^{3x}] = e^x(e^{2x}) + e^x(2e^{2x})$
[Derivative] Multiply [Exponential Rule - Multiplying]: $\displaystyle \frac{d}{dx}[e^{3x}] = e^{3x} + 2e^{3x}$
[Derivative] Combine like terms [Addition]: $\displaystyle \frac{d}{dx}[e^{3x}] = 3e^{3x}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

8 0

3 years ago