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3 years ago

Using two step equation how do I solve 16= (x + 3)^2

Mathematics

1 answer:

stellarik [79]3 years ago

4 0

Answer:

x=1.-7

Step-by-step explanation:

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How do i find the circumference of a circle

Molodets [167]

You have to do 3.14 times the diameter of the circle.

8 0

3 years ago

Read 2 more answers

the diameter of a cylindrical construction pipe is 4 ft. if the pipe is 19 ft long, what s it’s volume?

STALIN [3.7K]

Answer:

76 $\pi$ or 238.76 $units^{3}$

Step-by-step explanation:

The volume of a cylinder is V = $\pi r^{2} h$

Here the radius is r = $\frac{1}{2} d$ = $\frac{1}{2}(4)=2$

The height is given as 19 ft

Then plug in all the numbers into the equation

V = $\pi (2^{2})(19) = 76\pi = 238.76 units^{3}$

4 0

3 years ago

Can someone please help me

PtichkaEL [24]

Answer:

The size is 37.5 degrees

Step-by-step explanation:

The total angle in the triangle is 180

Since the other two angles are congruent. it means that they are equal

Let us call each of the angles x

Mathematically,

x + x + 105 = 180

2x = 180-105

2x = 75

x = 75/2

x = 37.5

7 0

3 years ago

(12,10),(-2,r), m=-4

Savatey [412]

Answer:66

Step-by-step explanation:

Y=mx+b

10=-4*12+b

10=-48+b

b=58

r=-4(-2)+58

r=66

4 0

3 years ago

A random sample of 64 observations produced a mean value of 84 and standard deviation of 5.5. The 90% confidence interval for th

ASHA 777 [7]

Answer: The 90% confidence interval for the population mean μ is between 82.85 and 85.15,

Step-by-step explanation:

When population standard deviation is not given ,The confidence interval population proportion is given by ( $\mu$ ):-

$\overline{x}\pm t^*\dfrac{s}{\sqrt{n}}$

, where n= Sample size.

s= Sample standard deviation

$\overline{x}$ = sample mean

t* = Critical t-value (Two-tailed)

As per given , we have

$\overline{x}=84$

n= 64

Degree of freedom : df = n-1=63

s= 5.5

Significance level : $\alpha=1-0.90=0.1$

Two-tailed T-value for df = 63 and $\alpha=1-0.90=0.1$ would be

$t_{\alpha/2,df}=t_{0.05,63}=1.669$ (By t-distribution table)

i.e. t*= 1.669

The 90% confidence interval for the population mean μ would be

$84\pm (1.669)\dfrac{5.5}{\sqrt{64}}$

$=84\pm (1.669)\dfrac{5.5}{8}$

$\approx84\pm 1.15$

$=(84-1.15,\ 84+1.15)=(82.85,\ 85.15)$

∴ The 90% confidence interval for the population mean μ is between 82.85 and 85.15,

6 0

3 years ago