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3 years ago

Write the sentence as an inequality. A number is less than 6 and greater than 2

Mathematics

1 answer:

Rina8888 [55]3 years ago

4 0

Answer:

6 > x > 2

Step-by-step explanation:

This could be wrong, but if the number is less than six, and greater than two, itd look like that!

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1) You are designing a new kiddie soccer arena. The area of the rectangular

nikdorinn [45]

Answer:

The length of the rectangular field is 12 ft and the width is 5 ft.

Step-by-step explanation:

The area of a rectangle is:

$\text{Area} = \text{length}\times \text{width}$

The area of a rectangular field is, <em>A</em> = 60 ft.

The length of the field is:

l = w + 7

Compute the width of the field as follows:

$\text{Area} = \text{length}\times \text{width}$

$60=(w+7)\times w\\\\60=w^{2}+7w\\\\w^{2}+7w-60=0\\$

Factorize the last equation by splitting the middle term as follows:

$w^{2}+7w-60=0\\w^{2}+12w-5w-60=0\\w(w+12)-5(w+12)=0\\(w-5)(w+12)=0$

Now, since the width of rectangular field cannot be negative, the width is 5 ft.

Compute the length as follows:

l = w + 7

= 5 + 7

= 12

The length of the rectangular field is 12 ft.

7 0

3 years ago

What is another way to write x 4/3

pentagon [3]

Answer:

x 1 1/3

Step-by-step explanation:

4/3 is equal to 1 1/3

5 0

3 years ago

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

3 years ago

Name the place of the hylighted digits,then write the value of the digits 35.052

Alex

<span>Name the place of the hylighted digits,then write the value of the digits 35.052
Answer: tens</span>

3 0

4 years ago

A guest is traveling in a cab to reach his destination he traveled 8 blocks at a rate of 1.50$ per block what is his cab fee

babymother [125]

The cab fee is about 25:000

7 0

3 years ago