All categories

3 years ago

Write the sentence as an inequality. A number is less than 6 and greater than 2

Mathematics

1 answer:

Rina8888 [55]3 years ago

4 0

Answer:

6 > x > 2

Step-by-step explanation:

This could be wrong, but if the number is less than six, and greater than two, itd look like that!

You might be interested in

Y< 1/4x and y< -6x+6 are graphed on the coordinate plane

slavikrds [6]

Answer:

See attachment

Step-by-step explanation:

To graph

$y \: < \: \frac{1}{4} x$

You first graph the boundary line

$y = \frac{1}{4} x$

This is a dashed line going through the origin with slope 1/4.

We test the point (0,1) to get: 1<0 which is false. So we shade the lower half-plane.

To graph

$y \: < \: - 6x + 6$

We first graph line

$y = - 6x + 6$

By plotting (0,6), and (1,0)

We draw a dashed boundary line.

We test the origin:

0<6 which is true so we shade the left half-plane .

The intersection of both shaded regions represent the solution set.

The graph us shown in attachment.

3 0

4 years ago

Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

According to the Figure Given:

Total Horizontal Distance = 14 in

Length = 6 in

To Find :

The Area of the composite figure

Solution:

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

3 0

2 years ago

10.31988 to the nearest hundredth

mezya [45]

Answer:

10.32

Step-by-step explanation:

10.31988

the 9 makes the 1 to a 2 so...

10.32

5 0

3 years ago

Read 2 more answers

Need help with this...

garri49 [273]

Answer:

right out the equation solve

Step-by-step explanation:

7 0

3 years ago

Write the slope intercept form Through:(1,-5) and(4, -1)

erastovalidia [21]

Answer:

Slope intercept form is

$y=\frac{4}{3} x- \frac{19}{3}$

4 0

3 years ago