Answer:
Exactly two distinct zeros
Step-by-step explanation:
y = 2(x-1) (x + 4)
Plug y = 0
0 = 2(x-1) (x + 4)
0/2 = (x-1) (x + 4)
(x-1) (x + 4) = 0
(x-1) = 0 or (x + 4)= 0
x = 1 or x = - 4
Here, x has two distinct roots, therefore given quadratic relation has Exactly two distinct zeros.
Statement 3 is QR=RT. This can be validified by the reason of Transitive Property of Equality. This property is applied when the situation is if a=c and b=c, then a=b. The same is true for QR=59 and RT=59, then QR=RT.
Answer:
2 * 2 * 3
Step-by-step explanation:
yes, six times a number of n is 6n the greater than or equal ≥ and y plus two is y + 2
