The table shows the measured amount of a medication

draw and lable a circle that has diameter more than 5 inches,but less than 10 inches. estimate its circumference and them find i

dsp73

Using a graph tool
see the attached figure

Let
D----------> the diameters of the circle O
D=8 in
D=8 in is < 10 in and D=8 in is > 5 in
the center of the circle is the point (0,0)
the circumference of the circle=pi*D-------> 8*pi in

the circumference value estimate is about 24 in
the circumference value using a calculator is ----> 8*pi----> 25.13 in

the difference in the exact value and the estimate value is
25.13-24--> 1.13 in

4 0

3 years ago

Which is an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12?

Bond [772]

Answer:

An equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

$y=-\frac{1}{5}x+\frac{13}{5}$

Step-by-step explanation:

Given the equation

$5x - y = 12$

converting the line into the slope-intercept form y = mx+b, where m is the slope

$-y = 12-5x$

$y = 5x-12$

The slope of the line = m = 5

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

Therefore, the slope of new line = – 1/m = -1/5 = -1/5

Using the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where m is the slope of the line and (x₁, y₁) is the point

substituting the slope of new line = -1/5 and (-2, 3)

$y-y_1=m\left(x-x_1\right)$

$y-3=-\frac{1}{5}\left(x-\left(-2\right)\right)$

$y-3=-\frac{1}{5}\left(x+2\right)$

Add 3 to both sides

$y-3+3=-\frac{1}{5}\left(x+2\right)+3$

$y=-\frac{1}{5}x+\frac{13}{5}$

Therefore, an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

$y=-\frac{1}{5}x+\frac{13}{5}$

5 0

3 years ago

2. The side of a square exceeds the side of

Anastaziya [24]

Answer:

$x=30cm$

$y=30+5=>35cm$

Step-by-step explanation:

From the question we are told that

Sides difference $\triangle x= 5cm$

Area difference $\triangle a=326sq.cm$

Let first square be A

Let second square be B

Generally the area of a square is mathematically given by

Area of a square $A=x*x=x^2$

Area of a square $B=(x+5)^2=x^2+25+10x$

$Area \A - Area\ B =325$

Therefore from the equations above

$x^2+25x+10-x^2=325$

$10x=325-25$

$x=300/10$

$x=30cm$

Therefore

Side of the first square

$x=30cm$

Side of the second square.

$y=>30+5=35cm$

Check answer

$35^2-30^2=325$

4 0

3 years ago

Answer only if you know<br><br> HELP PART A AND PART B

VARVARA [1.3K]

Answers:

Part A) There is one pair of parallel sides
Part B) (-3, -5/2) and (-1/2, 5/2)

====================================================

Explanation:

Part A

By definition, a trapezoid has exactly one pair of parallel sides. The other opposite sides aren't parallel. In this case, we'd need to prove that PQ is parallel to RS by seeing if the slopes are the same or not. Parallel lines have equal slopes.

------------------------

Part B

The midsegment has both endpoints as the midpoints of the non-parallel sides.

The midpoint of segment PS is found by adding the corresponding coordinates and dividing by 2.

x coord = (x1+x2)/2 = (-4+(-2))/2 = -6/2 = -3

y coord = (y1+y2)/2 = (-1+(-4))/2 = -5/2

The midpoint of segment PS is (-3, -5/2)

Repeat those steps to find the midpoint of QR

x coord = (x1+x2)/2 = (-2+1)/2 = -1/2

y coord = (x1+x2)/2 = (3+2)/2 = 5/2

The midpoint of QR is (-1/2, 5/2)

Join these midpoints up to form the midsegment. The midsegment is parallel to PQ and RS.

7 0

3 years ago

Here it is pls answer

kirza4 [7]

Answer:

1,100

Step-by-step explanation:

Round all numbers first

200, 200, 200, 200, 100, 200

then add to get 1,100

i always get these questions wrong so be careful lol

3 0

3 years ago