Answer:
8
Step-by-step explanation:
1,2,3,4,6,8,12,24
Answer:
8p∧2 ± p - 1 ± 13/p ± 1
Step-by-step explanation:
Divide (9p2 + 8p3 + 12) ÷ (p + 1) and it equals 8p∧2 ± p - 1 ± 13/p ± 1
You could divide 100 by 4 which is 25. Then divide 69 by 4 which would bring you to 17.25. 169 divided by 4 is 42.25. The answer would be 42 with a remainder of 1
1,100÷5= 220:) or 1,100×5= 5,500
Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1