Answer:
x= 381.56
Step-by-step explanation:
.......................
Answer: -5100
<u>Step-by-step explanation:</u>
![\sum^4_1[100(-4)^{n-1}]\qquad \rightarrow \qquad a_1=100\ \text{and r = -4}\\\\\\S_n=\dfrac{a_1(1-r^n)}{1-r}\\\\\\\\S_4=\dfrac{100(1-(-4)^4)}{1-(-4)}\\\\\\.\quad=\dfrac{100(1-256)}{1+4}\\\\\\.\quad=\dfrac{100(-255)}{5}\\\\.\quad=20(-255)\\\\.\quad=-5100\\](https://tex.z-dn.net/?f=%5Csum%5E4_1%5B100%28-4%29%5E%7Bn-1%7D%5D%5Cqquad%20%5Crightarrow%20%5Cqquad%20a_1%3D100%5C%20%5Ctext%7Band%20r%20%3D%20-4%7D%5C%5C%5C%5C%5C%5CS_n%3D%5Cdfrac%7Ba_1%281-r%5En%29%7D%7B1-r%7D%5C%5C%5C%5C%5C%5C%5C%5CS_4%3D%5Cdfrac%7B100%281-%28-4%29%5E4%29%7D%7B1-%28-4%29%7D%5C%5C%5C%5C%5C%5C.%5Cquad%3D%5Cdfrac%7B100%281-256%29%7D%7B1%2B4%7D%5C%5C%5C%5C%5C%5C.%5Cquad%3D%5Cdfrac%7B100%28-255%29%7D%7B5%7D%5C%5C%5C%5C.%5Cquad%3D20%28-255%29%5C%5C%5C%5C.%5Cquad%3D-5100%5C%5C)
Answer:
Given: Principal(P) = $ 5000 , T = 3.5 years and R = 5%.
Using the formula of Simple Interest (I) given by;
.......[1] , where P is the Principal amount of money to be invested, R be the rate of interest and T be the time.
Substitute the given values of P , R and T in [1] we have;
Simplify:
An Ending balance is calculated by subtracting cash outflows, interest paid for financing and principal paid on financing.
Ending Balance = $ 5000 + $ 175 = $ 5,175.
Therefore, the ending balance is $ 5,175
The graph represented in the figure shows a set of linear equations each of which is represented a straight line.
Step-by-step explanation:
System of Equation can be referred to as an assortment of equations to be dealt with. Common examples include linear equations and non-linear equations such as a parabola, hyperbola etc.
Linear set of equations are the most simple of equation depicting a linear relationship between two variables.
E.g. Y=4x+3
here y and x share a linear relationship which is defined by the straight-line graph "4x+3"
Similarly in the graph lines, two straight lines are depicted which symbolises that the et of the equation is linear in character.
