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serg [7]
3 years ago
15

Is this correct????????

Mathematics
2 answers:
scoundrel [369]3 years ago
4 0
You're right ^^ if u wanna know why, I can answer it for u :)

*edit* I used the wrong your XD
Vsevolod [243]3 years ago
4 0

Yes that's correct, they involve variables


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I need help, I don't just need to answer I need to know the steps on how to solve it asap
Likurg_2 [28]
Your goal when solving problems like these are to get V by itself. Meaning, on one side of the equal sign. So first you are to add -2 over to the side with the 4. Then multiple that by 11. To undo the division
3 0
2 years ago
The area of a circle is 1256 square inches what is the length of its radius
Otrada [13]
The formula of the area of a circle is : A= \pi R^2

You know that the area is 1256.

So : 1256= \pi R^2

Divide both sides by \pi :

\frac{1256}{\pi}=R^2

<span> take the square root of both sides in order to obtain r :

</span>\sqrt{ \frac{1256}{ \pi }}=R
20=R
<span>
In short, the answer would be 20 (i have rounded).

Hope this helps !

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</span>

6 0
3 years ago
During the first hour of operation the farm stand owner sold 15% of the apples he had. On the second hour he sold 20% of the rem
liraira [26]

Answer:

 3.825 kg apples.

Step-by-step explanation:

Let x kg be the amount of apples stand owner had initially.

We have been given that during the first hour of operation the farm stand owner sold 15% of the apples he had. Then the amount of sold apples will be:

\text{The amount of sold apples during 1st hour}=\frac{15}{100}x=0.15x

\text{The amount of remaining apples after 1st hour}=x-0.15x

\text{The amount of remaining apples after 1st hour}=0.85x

On the second hour he sold 20% of the remaining apples. So the amount of sold apples on the second hour will be 20% of 0.85x.

\text{The amount of sold apples during 2nd hour}=0.85x*\frac{20}{100}  

\text{The amount of sold apples during 2nd hour}=0.85x\times 0.20  

\text{The amount of sold apples during 2nd hour}=0.17x

During the second hour 25.5 kg of apples were sold, so we can set up an equation as:

25.5=0.17x

\frac{25.5}{0.17}=\frac{0.17x}{0.17}

150=x

So, stand owner had initially 150 kg of apples.

\text{The amount of remaining apples after 2nd hour}=0.85x-0.17x

\text{The amount of remaining apples after 2nd hour}=0.68x

On the third hour he sold 25% of the remaining apples. So the amount of sold apples on the 3rd hour will be 25% of 0.68x

\text{The amount of sold apples during 3rd hour}=0.68x*\frac{25}{100}

\text{The amount of sold apples during 3rd hour}=0.68x*0.25

\text{The amount of sold apples during 3rd hour}=0.17x  

\text{The amount of remaining apples after 3rd hour}=0.68x-0.17x

\text{The amount of remaining apples after 3rd hour}=0.51x

As remaining apples were sold 5% more each following hour.

\text{The amount of sold apples during 4th hour}=0.51x*\frac{5}{100}

\text{The amount of sold apples during 4th hour}=0.51x*0.05

\text{The amount of sold apples during 4th hour}=0.0255x

Let us substitute x=150 into above equation we will get,

\text{The amount of sold apples during 4th hour}=0.0255*150

\text{The amount of sold apples during 4th hour}=3.825

Therefore, 3.825 kg of apples were sold during the 4th hour.

7 0
3 years ago
The box plots show the average wind speeds, in miles per hour, for two different islands.
rewona [7]

Answer:

THE THIRD OPTION

Step-by-step explanation:

5 0
3 years ago
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Find the height of the pole if the shadow of a boy 5 ft. 6 in. tall is 2 ft. and the shadow of the pole is 2 yards.
oee [108]
2*2-1/3 yards= 4-2/ yards =14 feet.
THE SHADOW IS HALF THE HEIGHT OF OBJECT, SINCE A 6 FEET BOY CASTS A 3 FEET . SO THE POLE WILL BE TWICE THE LENGTH OF ITS SHADOW. try this
8 0
3 years ago
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