Question

A rectangle has a perimeter of 64 inches. The length is 6 more than the width.

Answer 1

Let width be x so
Length is equal to x+6
Perimeter= 2(l+b)
So perimeter=2(x+x+6)
P=2(2x+6)
4x+12=64 (given)
Send 12 to the other side then,
4x=64-12=52
X=52/4=13