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Andre45 [30]
4 years ago
6

A rectangle has a perimeter of 64 inches. The length is 6 more than the width.

Mathematics
1 answer:
BigorU [14]4 years ago
3 0
Let width be x so
Length is equal to x+6
Perimeter= 2(l+b)
So perimeter=2(x+x+6)
P=2(2x+6)
4x+12=64 (given)
Send 12 to the other side then,
4x=64-12=52
X=52/4=13
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Find the area of the polygon.<br><br> 2cm 2cm 3m
steposvetlana [31]

Answer:

If its a specific shape then probably the formula would be different.

If it were to be a parallelogram then multiply all given lengths

2 x 2 x 3 = 12cm

4 0
3 years ago
Make x the subject of the formula for Q20.
saul85 [17]

Answer:

x = \sqrt{m(\frac{a}{b})^{2} +n  }

Step-by-step explanation:

a\sqrt{(\frac{x^{2} - n }{m}) } = \frac{a^{2} }{b}

\sqrt{\frac{x^{2} - n }{m} } = \frac{a}{b}   [Divide both sides by a]

\frac{x^{2} - n}{m} = (\frac{a}{b} )^{2}   [Square both sides]

x^{2} -n = m(\frac{a}{b} )^{2}   [Multiply both sides by m]

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7 0
3 years ago
Select all the points that are on the line through LaTeX: (0,5)( 0 , 5 ) and LaTeX: (2,8)( 2 , 8 ). Group of answer choices LaTe
Ivenika [448]

Answer:

The points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

Step-by-step explanation:

The equation of the line passing through two points (x_1,y_1) and (x_2,y_2) is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

So, the equation of the line passing through two points (0,5) and ( 2, 8 ) is

y-5=\frac{8-5}{2-0}(x-0)

\Rightarrow y=1.5x+5\cdots(i)

For the point (4,11), pout x=4 in equation (i), we have

y=1.5\times4 +5=11, which is given y coordinate, hence this point (4,11) lies on the line.

For the point (5,10), pout x=5 in equation (i), we have

y=1.5\times5 +5=12.5, which is not the given y coordinate, hence the point (5,10) doesn't lie on the line.

For the point (6,14), pout x=6 in equation (i), we have

y=1.5\times6 +5=14, which is the given y coordinate, hence the point (6,14)  lies on the line.

For the point (30,50), pout x=30 in equation (i), we have

y=1.5\times30 +5=50, which is the given y coordinate, hence the point (30,50) lies on the line.

For the point (40,60), pout x=40 in equation (i), we have

y=1.5\times40 +5=65, which is not the given y coordinate, hence the point (40,60) doesn't lie on the line.

Hence, the points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

4 0
3 years ago
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These are 45-45-90 triangles, whose hypotenuses are \sqrt{2} times their legs. Given a side of length 1, for example, the diagonal length is \sqrt{2}\approx 1.4142. The first few ordered pairs (x,y) in the table would be (1,1.41),(2,2.83),(3,4.24),(4,5.66),...

5 0
4 years ago
Find two integers whose sum is 5 and product is 4
gregori [183]

Answer:

1 and 4

Step-by-step explanation:

1+4=5

1 x 4=4

6 0
4 years ago
Read 2 more answers
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