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Sphinxa [80]
2 years ago
12

How to differentiate this

Mathematics
1 answer:
Art [367]2 years ago
6 0

y=t^3\,\,\,x=\sqrt{2t}+1\rightarrow t=\frac{(x-1)^2}{2}\\\rightarrow y=\frac{1}{8}(x-1)^6\\\frac{dy}{dx}=\frac{3}{4}(x-1)^5

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A toy rocket is launched vertically from 5 feet above ground level with an initial velocity of 112 feet per second. The height h
Masja [62]

Answer:

Step-by-step explanation:

a)The height h after t seconds is given by the equation h(t)=-16t^2+112t+5.

Where 5 represents 5feet above the ground and this is the height from which the rocket was launched.

The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the rocket.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

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Vertex = - - 112/32= 3.5

So the rocket will attain maximum height at 3.5 seconds.

It will also take 3.5 seconds to reach the ground. This means it will take a total of 3.5 seconds + 3.5 seconds

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b) to find time it will take to be 100 feet above the ground,

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Using general quadratic equation formula,

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t = 0.9875 or t = 6.0125

So it will take 0.9875 or approximately 1 second to be 100 feet above the ground

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3 years ago
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