Question

How to differentiate this

Answer 1

$y=t^3\,\,\,x=\sqrt{2t}+1\rightarrow t=\frac{(x-1)^2}{2}\\\rightarrow y=\frac{1}{8}(x-1)^6\\\frac{dy}{dx}=\frac{3}{4}(x-1)^5$