Answer:
(sin^2 w + 1) / cos w.
Step-by-step explanation:
Note: sec w = 1 / cos w and csc w = 1/ sin w.
So we have:
(sec w(1 + csc^2 w)) / (csc^2 w)
= 1/cos w ( 1 + 1/ sin^2 w) / (1 / sin^2 w)
= ( 1/ cos w + 1 / sin^2 w cos w) * sin^2 w
= sin^2 w/ cos w + sin^2 w / (sin^2 w cos w)
= sin^2 w / cos w + 1 / cos w
= (sin^2 w + 1) / cos w.
Answer:
Expected number of free throws in 60 attempts:
Best player = 48
2nd best player = 45
3rd best player = 42
Step-by-step explanation:
Solution:-
- The probability that best player makes free throw, p1 = 0.8
- The probability that second-best player makes free throw, p2 = 0.75
- The probability that third-best player makes free throw, p3 = 0.70
- Total number of attempts made in free throws, n = 60.
- The estimated number of free throws that any player makes is defined by:
E ( Xi ) = n*pi
Where, Xi = Player rank
pi = Player rank probability
- Expected value for best player making the free throws would be:
E (X1) = n*p1
= 60*0.8
= 48 free throws
- Expected value for second-best player making the free throws would be:
E (X2) = n*p2
= 60*0.75
= 45 free throws
- Expected value for third-best player making the free throws would be:
E (X3) = n*p3
= 60*0.70
= 42 free throws
Answer:
0.75
Step-by-step explanation:
Each 1/4 is a quarter so multiply 0.25*3 which equals 0.75
Y= 21 so HQE = 42 and AQG= 21
