Kirsten walked 230 meters in 50 seconds. What was Kirsten's speed?

Mathematics

2 answers:

tankabanditka [31]3 years ago

8 0

4.6 is her speed per second. it's the constant rate of how much she walks per second.

choli [55]3 years ago

3 0

4.6 meters per second was her walking speed

You might be interested in

Work out m and c for the line: ? y = x + 6

lapo4ka [179]

Well your c value is already there (6) as the standard equation for a line is
y = mx + c

To find the gradient (M) plot two points on the line.

Then label each co ordinate X1 and X2 and then Y1 and Y2

Then subtract your y1 from y2 and then x1 from x2.

For example :if your coordinates were (1,2) (3,4) you would do
4-2 and 3-1

These answers become your “changes” now do change in y / change in x

In terms of the Example you would do 2/2 which would be 1 and the M value would be 1

Hope that isn’t too confusing

7 0

3 years ago

Associative property <br><br> Commutative property <br><br> Distributive property

inysia [295]

Answer:

Distributive Property

Step-by-step explanation:

5 0

3 years ago

32. Which of the following is horizontal ellipse

maria [59]

Answer:

b. 16x² + 25y² = 1

Step-by-step explanation:

Only one of them has a < b in ax² + by² = c formula, making its graph horizontal

All the rest are vertical, see attached

6 0

3 years ago

Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe

solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for $p$ such that $1000p(1-p)$ is maximized. Once we have that $p$ , we can easily find the answer to part b.

Finding the value that maximizes $1000p(1-p)$ is the same as finding the value that maximizes $p(1-p)$ , just on a smaller scale. So, we really want to maximize $p(1-p)$ . To do this, we will do a trick called completing the square.

$p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4$ .

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of $p$ such that the inner part of the square term is equal to $0$ .