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Alla [95]
3 years ago
6

Which is the equation of a line that has a slope of -2/3 and passes through point

Mathematics
1 answer:
never [62]3 years ago
5 0

We have to find b

  • (-3,-1)
  • m=-2/3

\\ \sf\longmapsto y=mx+b

\\ \sf\longmapsto -1=\dfrac{-2}{3}(-3)+b

\\ \sf\longmapsto -1=-2(-1)+b

\\ \sf\longmapsto -1=2+b

\\ \sf\longmapsto b=-3

Now put in equation

\\ \sf\longmapsto y=\dfrac{-2}{3}x-3

Option D

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A bag has 12 red marbles and 6 green marbles. Half of the green marbles are made of plastic. A marble is selected at random from
Degger [83]

Answer:

1/6 is the probability of it being a green plastic marble.

Step-by-step explanation:

Note that there are 18 marbles in all (12 + 6 = 18).

Half of the green marbles (6) are made of plastic: 6/2 = 3

From the information above, we see that 3 green marbles are made of plastic. There are 18 marbles in all.

Divide, and simiplify.

(3/18)/(3/3) = 1/6

1/6 is the probability of it being a green plastic marble.

~

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3 years ago
What is the measure? Would appreciate any help!
Luba_88 [7]

Answer:

If I'm not wrong, angle O should be 62°!

Step-by-step explanation:

since triangle MON and triangle DAY are equal, if we add 75° and 43° it would be 118°. We then subtract 118° from 180° and it should be 62°. :)

6 0
3 years ago
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What are the period and phase shift for f(x) = 3 tan(4x + π)?
Y_Kistochka [10]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal or "phase" shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}


now.. with that template above in mind, let's see yours


\bf \begin{array}{lllllll}
f(x)=&3tan(&4x+&\pi )\\
f(x)=&3tan(&4x+&1\pi )&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}

7 0
3 years ago
How to solve -5(x-3)=-25
gayaneshka [121]

-5(x-3)=-25

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    -15   -15

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÷-5    ÷-5

x = 8

4 0
3 years ago
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Vlada [557]

Answer:

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Step-by-step explanation:

4 0
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