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2 years ago

7

A baking class had 45 students on Monday and only 32 students on Tuesday. What was the change in percent? (Round to the nearest

hundredths)

1 answer:

andrey2020 [161]2 years ago

7 0

Answer:

28.89 percent

Step-by-step explanation:

45-32 is 13 and 13 is 28.89 percent of 45

Hope this helped!

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Jeff has 1/4 of the pizza left

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In Aunt Melly's attics there are also spiders and ants, the total of 136 legs and 20 heads. If a spider has 8 legs and an ant ha

anzhelika [568]

Answer:

Spiders=8

Ants=12

Step-by-step explanation:

Spider(s)=8 legs

Ants(a)=6 legs

Total legs=136

Total heads=20

8s+6a=136 (1)

s+a=20 (2)

From (2)

s=20-a

Substitute 20-a into (1)

8s+6a=136

8(20-a)+6a=136

160-8a+6a=136

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-2a=136-160

-2a=-24

a= -24/-2

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Substitute a=12 into (2)

s+a=20

s+12=20

s=20-12

s=8

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3 years ago

Right Triangle and Trigonometry , Please help!!! Will give Brainliest!!!

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That would be true because the adjacent side to B is 4 and the hypotenuse is 5 and the formula for cos b is adjacent/hypotenuse

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3 years ago

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3 years ago

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12.what is the probability that a boy and a girl chosen randsomly will be seniors?

zhenek [66]

$\frac{\textbf{1}}{\textbf{20}}$

Step-by-step explanation:

Probability= $\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$

Probability for a randomly chosen girl to be senior= $\frac{\text{number of senior girls}}{\text{total number of girls}}$

Probability for a randomly chosen girl to be senior= $\frac{7}{8+11+9+7}=\frac{7}{35}=\frac{1}{5}$

Probability for a randomly chosen boy to be senior= $\frac{\text{number of senior boys}}{\text{total number of boys}}$

Probability for a randomly chosen girl to be senior= $\frac{9}{10+7+10+9}=\frac{9}{36}=\frac{1}{4}$

For two independent events,

Probability for both event 1 and event 2 to take place= $\text{probability of event 1} \times \text{probability of event 2}$

Since choosing boys and girls is independent,

Probability for both boy an girl chosen to be senior= $\text{probability for boy to be senior}\times\text{probability for girl to be senior}$

Probability for both boy and girl chosen to be senior= $\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}$

So,required probability is $\frac{1}{20}$

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3 years ago