Question

Please help.... A rectangle has a length of (x + 4) centimeters and a width of 12x centimeters. If the perimeter is 26 centimeters, what is the width of the rectangle.

Answer 1

Answer:

The width of rectangle is $W=\frac{108}{13}\ cm$  or  $8\frac{4}{13}\ cm$

Step-by-step explanation:

we know that

The perimeter of rectangle is equal to

$P=2(L+W)$

where

L is the length of rectangle

W is the width of rectangle

we have

$P=26/ cm\\L=(x+4)/ cm\\W=12x\ cm$

substitute

$26=2(x+4+12x)$

solve for x

$26=2(13x+4)$

$26=26x+8$

$26x=26-8$

$26x=18$

$x=\frac{18}{26}$

simplify

$x=\frac{9}{13}$

Find the width of rectangle

$W=12x\ cm$

substitute the value of x

$W=12(\frac{9}{13})=\frac{108}{13}\ cm$

Convert to mixed number

$\frac{108}{13}\ cm=\frac{104}{13}+\frac{4}{13}=8\frac{4}{13}\ cm$