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finlep [7]
3 years ago
10

Luis rolled a number cube 60 times. He rolled the number 6 four times. Which is most likely the cause of the discrepancy between

Luis’s experimental outcome and the predicted outcome? He did not perform enough trials.
He performed too many trials.
He needs to add the number 6 to the number of times it occurred.
He needs to subtract the experimental outcome from the predicted outcome.
Mathematics
2 answers:
damaskus [11]3 years ago
5 0

Solution:

Number of times Luis has rolled the number cube= 60 times

Number of times the number 6 has been rolled= 4

As the number cube contains number from 1 to 6.

So, if number cube has been rolled 60 times then each of the number or number 6 must have been rolled atleast  10 times.

The cause of Discrepancy between Luis’s experimental outcome and the predicted outcome is that : Option (A) He did not perform enough trials.  


slega [8]3 years ago
4 0
He did not perform enough trials. The more trials you perform, the closer it gets to the predicted outcome.
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Does anyone know how to do this ?
goldenfox [79]

Answer: D) 32

Step-by-step explanation:

The area of a parallelogram equals its base times its height. Substitute the base and area into this formula to solve for the height:

A=bh

40=(5)(h)

h=8

If ABCD is a parallelogram, opposite sides are parallel, so AB is parallel to DC. If AB is parallel to DC, EB is parallel to DC. Since EB is parallel to DC, quadrilateral EBCD has at least one pair of parallel sides, making it a trapezoid. The area of a trapezoid is equal to \frac{h(b_{1}+b_{2})  }{2} where h is the height, b_{1} is one base, and b_{2} is the other base. Plug the necessary values into the formula:

A=\frac{h(b_{1}+b_{2})  }{2}

b_{1} =AB-AE\\DC=AB\\b_{1} =DC-AE\\b_{1} =5-2\\b_{1} =3

b_{2} =5

h=8

A=\frac{8(3+5)}{2}

A=32

The answer is D) 32.

6 0
3 years ago
The citizens of a city were asked to choose their favorite pet. The circle graph shows how the citizens answered. If 65,000
White raven [17]

Answer:

Dogs: 14,300 people

Snakes: 3,900 people

8 0
2 years ago
Calculate the average rate of change of the given function f over the intervals [a, a + h] where h = 1, 0.1, 0.01, 0.001, and 0.
Delicious77 [7]

Step-by-step explanation:

average rate of change of function is given by :

f= (f(a+h)-f(a))/h

where

f(x)=3x

and a= 7

so inserting values is formula for h=1

f=(f(7+1)-f(7))/1

f= f(8)-f(7)= 3(8)-3(7)=24-21=3

now for h= 0.1

f=(f(7+0.1)-f(7))/0.1=(f(7.1)-f(7))/0.1=(3(7.1)-3(7))/0.1

f=3

similarly average rate of change of given function is same for all given step sizes.

6 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!
Lelechka [254]

Answer:

Step-by-step explanation:

(8x²-18x+10)/(x²+5)(x-3)

express the expression as a partial fraction:

(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +bx+c/x²+5

both denominator are equal , so require only work with the nominator

(8x²-18x+10)=(x²+5)A+(x-3)(bx+c)

8x²-18x+10= x²A+5A+bx²+cx-3bx-3c

combine like terms:

x²(A+b)+x(-3b+c)+5A-3c

(8x²-18x+10)

looking at the equation

A+b=8

-3b+c=-18

5A-3c=10

solve for A,b and c (system of equation)

A=2 , B=6, and C=0

substitute in the value of A, b and c

(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +(bx+c)/x²+5

(8x²-18x+10)/[(x^2+5)(x-3)] = 2/x-3 + (6x+0)/(x²+5)

(8x²-18x+10)/[(x^2+5)(x-3)] =

<h2>2/(x-3)+6x/x²+5</h2>

(4x+2)/[(x²+4)(x-2)]

(4x+2)/[(x²+4)(x-2)]= A/(x-2) + bx+c/(x²-2)

(4x+2)=a(x²-2)+(bx+c)(x-2)

follow the same step in the previous answer:

the answer is :

<h2>(4x+2)/[(x²+4)(x-2)]= 5/4/(x-2) + (3/2 -5x/4)/(x²+4)</h2>

8 0
3 years ago
Round to the nearest ten thousand 15,510
Shalnov [3]

Answer:

20,000

Step-by-step explanation:

The 5 in the thousands place  makes it round to 20,000

8 0
3 years ago
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