A dihybrid cross tracks two traits. Both parents are heterozygous, and one allele for each trait exhibits complete dominance *. This means that both parents have recessive alleles, but exhibit the dominant phenotype. The phenotype ratio predicted for dihybrid cross is 9:3:3:1. (There's a calculator on google that show the outcomes just to let ya know) hope it's correct .
when you perform a dihybrid cross with two heterozygous individuals for the two traits, what is the expected phenotypic ratio?
HhBb x HhBb= HHBB, HhBb, HhBb, hhbb
3:1
Explanation:
This results into two homozygous and two heterozygous, one homozygous is dominant while the other is recessive, although out of the four offspring three are dominant over one recessive
Normal cells have a reset phase where they don't divide if there is n need for them unlike cancer cells where they divide rapidly and they don't have that reset phase
