28. 5/7(x)=20
X=28
Hope this helps! :)
<span>The graph you plotted is the graph of f ' (x) and NOT f(x) itself. </span>
Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get
f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24
So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5
<span>f ' (x) = (x-4)(6-2x)
</span><span>f ' (3.5) = (3.5-4)(6-2*3.5)
</span>f ' (3.5) = 0.5
The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.
So the final answer is C) 3
Answer:
Step-by-step explanation:
Hypotenuse = x
Base = 4
Perpendicular = 
<u>Using Pythagoras Theorem:</u>
![\sf H^2 = P^2 + B^2\\\\ x^2 = (\sqrt{84} )^2 + (4)^2\\\\x^2 = 84 + 16\\\\x^2 = 100\\\\Taking \ sq \ root \ on \ both \ sides\\\\x = 10\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20H%5E2%20%3D%20P%5E2%20%2B%20B%5E2%5C%5C%5C%5C%20x%5E2%20%3D%20%28%5Csqrt%7B84%7D%20%29%5E2%20%2B%20%284%29%5E2%5C%5C%5C%5Cx%5E2%20%3D%2084%20%2B%2016%5C%5C%5C%5Cx%5E2%20%3D%20100%5C%5C%5C%5CTaking%20%5C%20sq%20%5C%20root%20%5C%20on%20%5C%20both%20%5C%20sides%5C%5C%5C%5Cx%20%3D%2010%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
7,830
Step-by-step explanation:The answer is 7830 becuase frogs are cool and can swim about 4 feet every 7 years
