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aleksley [76]
3 years ago
9

The quotient rule for exponents states that bm bn=​_______, b≠0 . When dividing exponential expressions with the same nonzero​ b

ase, _______ the exponents.
Mathematics
1 answer:
wariber [46]3 years ago
3 0

Answer:

The quotient rule for exponents states that b^{m}\div b^{n}=b^{m-n}.

When dividing exponential expressions with the same nonzero​ base, <u>subtract</u> the exponents.

Step-by-step explanation:

Some rules to solve exponents are:

  • x^{0}=1
  • (x^{m})^{n}=x^{mn}
  • x^{-n}=\frac{1}{x^{n}}
  • x^{m}\cdot x^{n}=x^{m+n}
  • \frac{x^{m}}{x^{n}}=x^{m-n}

The quotient rule for exponents states that:

b^{m}\div b^{n}=b^{m-n}.

When dividing exponential expressions with the same nonzero​ base, <u>subtract</u> the exponents.

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Solve the inequality x^2 -2x - 8 &gt;0​
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8 0
2 years ago
Need help please and Thank you
Novosadov [1.4K]
Top left:
7x-44 = 4x+4
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7 0
3 years ago
Which two values of x are roots of the polynomial below? x^2-3x+5
Gemiola [76]

Given:

Polynomial x^2-3x+5

To find:

The values of x.

Solution:

x^2-3x+5=0

Quadratic equation formula:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here a=1, b=-3, c=5.

Substitute the values in the formula, we get

$x=\frac{-(-3) \pm \sqrt{(-3)^{2}-4 \cdot 1 \cdot 5}}{2 \cdot 1}

$x=\frac{3 \pm \sqrt{9-20}}{2}

$x=\frac{3 \pm \sqrt{-11}}{2}

$x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}

Option E and option F are the roots of the polynomial.

The values of x are x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}.

7 0
3 years ago
6,000 multiplied by power of 10
larisa86 [58]
An easy way of finding the answer to your question is by using a scientific calculator. When I plugged in 6,000^10 it gave me 6.0466176x10^37. Yes the answer is in scientific notation, but if you want the answer shortened out to the nearest hundredth place the answer is 6.05.
7 0
3 years ago
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