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aleksley [76]
3 years ago
9

The quotient rule for exponents states that bm bn=​_______, b≠0 . When dividing exponential expressions with the same nonzero​ b

ase, _______ the exponents.
Mathematics
1 answer:
wariber [46]3 years ago
3 0

Answer:

The quotient rule for exponents states that b^{m}\div b^{n}=b^{m-n}.

When dividing exponential expressions with the same nonzero​ base, <u>subtract</u> the exponents.

Step-by-step explanation:

Some rules to solve exponents are:

  • x^{0}=1
  • (x^{m})^{n}=x^{mn}
  • x^{-n}=\frac{1}{x^{n}}
  • x^{m}\cdot x^{n}=x^{m+n}
  • \frac{x^{m}}{x^{n}}=x^{m-n}

The quotient rule for exponents states that:

b^{m}\div b^{n}=b^{m-n}.

When dividing exponential expressions with the same nonzero​ base, <u>subtract</u> the exponents.

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4 0
2 years ago
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Sergeu [11.5K]
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5 0
3 years ago
Read 2 more answers
If f(x) = x3 – x2 – 3, which of the following is equal to g(x) = f(2 – x)?
Andru [333]

Answer:

-x^3+5x^2-8x+1, which is choice A

======================================

Work Shown:

f(x) = x^3 - x^2 - 3

f(x) = (x)^3 - (x)^2 - 3

f(2-x) = (2-x)^3 - (2-x)^2 - 3 ................ see note 1 (below)

f(2-x) = (2-x)(2-x)^2 - (2-x)^2 - 3 ........... see note 2

f(2-x) = (2-x)(4-4x+x^2) - (4-4x+x^2) - 3 ..... see note 3

f(2-x) = -x^3+6x^2-12x+8 - (4-4x+x^2) - 3 ..... see note 4

f(2-x) = -x^3+6x^2-12x+8 - 4+4x-x^2 - 3 ....... see note 5

f(2-x) = -x^3+5x^2-8x+1

----------

note1: I replaced every copy of x with 2-x. Be careful to use parenthesis so that you go from x^3 to (2-x)^3, same for the x^2 term as well.

note2: The (2-x)^3 is like y^3 with y = 2-x. We can break up y^3 into y*y^2, so that means (2-x)^3 = (2-x)(2-x)^2

note3: (2-x)^2 expands out into 4-4x+x^2 as shown in figure 1 (attached image below). I used the box method for this and for note 4 as well. Each inner box or cell is the result of multiplying the outside terms. Example: in row1, column1 we have 2 times 2 = 4. You could use the FOIL rule or distribution property, but the box method is ideal so you don't lose track of terms.

note4: (2-x)(4-4x+x^2) turns into -x^3+6x^2-12x+8 when expanding everything out. See figure 2 (attached image below). Same story as note 3, but it's a bit more complicated.

note5: distribute the negative through to ALL the terms inside the parenthesis of (4-4x+x^2) to end up with -4+4x-x^2


4 0
3 years ago
3.
Ber [7]
A. 7x

B. 8x-1

C. 6x+12

D. 3x +4

E. 13x-7
6 0
2 years ago
How to find the area of this figure
stiv31 [10]

Answer:

45 square units.

Step-by-step explanation:

Applying the pythagoras theorem:

Base of the bigger triangle = \sqrt{15^2 - 9^2} = \sqrt{144} = 12 units

Area of a triangle is given by \frac{1}{2} × base × height

The area of the bigger triangle is  \frac{1}{2} × 12 × 9 = 54 square units.

The area of the smallest triangle is  \frac{1}{2} × (12 - 10) × 9 = 9 square units.

The area of the figure( required triangle) is 54 - 9 = 45 square units.

3 0
3 years ago
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