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bogdanovich [222]
3 years ago
7

Which expression can you use to find 16÷45?

Mathematics
2 answers:
Serga [27]3 years ago
7 0

Answer:

☆<《<em><u>HOPE</u></em><em><u> </u></em><em><u>IT</u></em><em><u> </u></em><em><u>WILL HELP YOU</u></em><em><u> </u></em><em><u>》</u></em><em><u>></u></em><em><u>☆</u></em>

Step-by-step explanation:

Exprassion is 16/45--x=0

Elena-2011 [213]3 years ago
5 0
4*5/4*40 is the answer is you use the distributive property
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4 0
3 years ago
Could you explain what the answer is and why? I am not sure of how to do this
lidiya [134]
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8 0
3 years ago
Read 2 more answers
Each sequence has eight terms. Evaluate each related series. 1,-1,-3, . . . . . . -13
o-na [289]

The sum of the 8 terms of the series 1-1-3-5- ... -13 is -48

The given sequence is:

1,-1,-3,  . . -13

and there are 8 terms.

The related series of this sequence is:

1-1-3-5- ... -13

Notice that the series is an arithmetic series with:

first term, a(1) = 1

common difference, d = -1 - (1) = -2

last term, a(8) = -13

To find the sum of the series, use the sum formula:

S(n) = n/2 [(a(1) + a(n)]

Substitute n = 8, a(1) = 1, a(n) = a(8) = -13 into the formula:

S(8) = 8/2 [1 + (-13)]

S(9) = 4 . (-12) = -48

Learn more about sum of a series here:

brainly.com/question/14203928

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8 0
1 year ago
(X^3+3x^2-x+8)/(x-1)
ki77a [65]
Here is all of the work:

8 0
4 years ago
Simplify the expression:
Lelu [443]
\cfrac{(12-5)^7}{\left((3+4)^2\right)^2}= \cfrac{7^7}{(7^2)^2} =\cfrac{7^7}{7^4}=7^{7-4}=7^3=343
5 0
3 years ago
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