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nika2105 [10]
3 years ago
11

What are the names of the witches in the wizard of oz?

Mathematics
2 answers:
Anestetic [448]3 years ago
4 0
The Wicked Witch<span> of the West is not </span>named<span> in Baum’s books. However, in the 1910 silent film, The Wonderful </span>Wizard<span> of </span>Oz<span>, this </span>witch<span> is </span>named<span> Momba in the intertitles </span>
Alinara [238K]3 years ago
4 0
<span>Wicked Witch of the East, Good Witch of the North, Princes Glinda the Good Witch, Wicked Witch of the West</span>
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Can someone explain ?
Vika [28.1K]

Answer:

see below

Step-by-step explanation:

sqrt(90)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(9*10)

sqrt(9) sqrt(10)

3*sqrt(10)

8 0
3 years ago
A ladder, 14 feet long, is leaning against
PolarNik [594]

Answer:

12.12ft

Step-by-step explanation:

14² = 7² + x²

x² = 14² - 7²

x² = 196 - 49

x² = 147

x = √147

x = 12.12ft

6 0
3 years ago
Read 2 more answers
The product of 11/13 and 4 is:
kirza4 [7]

Answer:

11/13 x 4 = 3 5/13

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Two complex numbers are given byz1= 3 +j4 andz2= 2 +j3. Determine in both polar andCartesian forms
Marat540 [252]

Answer:

Cartesian

z₁= 3 +4*j

z₂= 2 +3*j

Polar

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

Step-by-step explanation:

for the complex numbers z the cartesian form of is

z= x + y*j

then

1) z₁= 3 +4*j (cartesian form)

2) z₂= 2 +3*j (cartesian form)

the polar form is

z= r* e^jθ

where

r= √(x²+y²) → r₁ = √(3²+4²) = 5 ,  r₂ = √(2²+3²) = √13

and

θ = tan⁻¹ (y/x)  → θ₁  = tan⁻¹ (4/3)= 0.927 rad , θ₂  = tan⁻¹ (3/2)= 0.982 rad

then

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

3 0
3 years ago
A student is solving the problem x^2 + 10x+ ___ = 16 + ___ by the method of completing the square. What number should the studen
kvv77 [185]

Answer:

I believe it could be any number because:

let y=any number

x^2+10x+y=16+y

x^2+10x+y-y=16+y-y

x^2+10x=16

you can add any number to both side and not change the solution.

5 0
3 years ago
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