Answer:
B = 61°
A = 29°
a = 10
Step-by-step explanation:
We are given;
c = 16, b = 14
Since we are told that C is a right angle, it means that C = 90°
Thus using sine rule, we have;
c/sin C = b/sin B
16/sin 90 = 14/sin B
16/1 = 14/sin B
sin B = 14/16
sin B = 0.875
B = sin^(-1) 0.875
B ≈ 61°
Now, since C is a right angle, it means that c will be the hypotenuse of the triangle.
Thus, from pythagoras theorem, If the other side of the triangle is a, then;
a² + b² = c²
a² + 14² = 16²
a² = 16² - 14²
a² = 256 - 156
a² = 100
a = √100
a = 10
Since we know B and C, we can find A because sum of angles in a triangle is 180°.
Thus;
A = 180 - (B + C)
A = 180 - (61 + 90)
A = 29°
They would be identical so it would be 114
Answer:
7 9/14
Step-by-step explanation:
1/2=7/14
1/7=2/14
7/14+2/14=9/14
5+2=7
Answer: B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
Step-by-step explanation:
Here are the options:
A There are more boys at Mark's school than at Leslie's school because the ratio 11 to 12 is greater than the ratio 41 to 48.
B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
C. There are more boys at Leslie's school than at Mark's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
At leslie's school the ratio of boys and girls is 11 to 12. This implies that the fraction of boys in the school to total students will be:
= 11/(11 + 12) = 11/23 = 0.4783
At Marks school the ratio of boys to girls is 41 to 48. Thus implies that the fraction of boys in the school to total students will be:
= 41 / (41 + 48) = 41/85= 0.4824
Based on the calculation, we can deduce that there are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.
