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iren [92.7K]
3 years ago
13

Please help me simplify this

Mathematics
2 answers:
lianna [129]3 years ago
8 0

\sqrt{2  \: +  \:  \sqrt{3} }  \:  +  \:  \sqrt{2  \:  -  \:  \sqrt{3} }  \:  -  \:  \sqrt{3 \:  +  \: 2 \sqrt{2} }  \:  -  \:  \sqrt{3 \:  -  \: 2 \sqrt{2} }
\sqrt{2 +  \sqrt{3} }  \:  +  \:  \sqrt{2 -   \sqrt{3}  }  \:  -  \:  \sqrt{ { (\sqrt{2 } + 1) }^{2} }  \:  -  \:  \sqrt{ {( \sqrt{2} - 1) }^{2} }
\sqrt{2 \:  +  \:  \sqrt{3} }  \:  +  \:  \sqrt{2 \:  -  \:  \sqrt{3} }  \:  -  \: 2 \sqrt{2}  \:  =  \:  - 0.378937

OleMash [197]3 years ago
5 0

Answer:

Step-by-step explanation:

the idea is

by assuming that (2+sqrt(3)) = a^2 + 2ab + b^2

let 2ab = sqrt(3) , then b =sqrt(3)/2a   (i)

let a^2 +b^2 = 2     (ii)

then substitute by (i) in (ii) and get a and b

then do this for every sqrt in your ask

finally you will get your answer

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Answer:

(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

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