Answer:
I think it’s A,C, and E
Step-by-step explanation:
I’m not for sure but if you plot those points in the shaded region for graph C, those should be correct .
Answer:
a
Step-by-step explanation:
no
Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000
What you have to do is add up the amount of total grade scores. 76+99+86+x. You get 261+x. you have to get 99% or higher
Answer:
40
Step-by-step explanation:
f(4) = 3(4²) - 2(4)
= 3(16) - 8
= 48 - 8
= 40
when x=4, f(x) = 40