Using Descarte's Rule of Signs, which are possible combinations of zeros for f(x)=2x4−8x3+12x2−16x+10?
1 answer:
There can be 4 or 1 possible combinations of zeros
You might be interested in
Answer:
Scales-No equal sides
Isosceles- 2 Equal
Equilateral-
Right-90 degree
Obtuse- Obtuse Angle
So if 54 is 100% then 200% is double therefore 200% of 54 is 108
43+48+42=133
(133+x)/4=50
133+x=200
x=67
Answer:
3 km
Step-by-step explanation:
<em>(NOTE: One kilometer is 1000 meters)</em>
Divide 3000 by 1000 to get 3
Answer:
I think it is B) 0
Step-by-step explanation: