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fenix001 [56]
2 years ago
13

Using Descarte's Rule of Signs, which are possible combinations of zeros for f(x)=2x4−8x3+12x2−16x+10?

Mathematics
1 answer:
zaharov [31]2 years ago
3 0
There can be 4 or 1 possible combinations of zeros
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nika2105 [10]

The discriminant of the given quadratic equation as in the task content can be evaluated by means of the formula; D = b²-4ac and it's value is; 13.

<h3>What is the discriminant of the quadratic equation as given in the task content?</h3>

According to the task content, it follows that the quadratic equation whose discriminant is to be determined is; x²-5x+3=0.

By comparison with the standard form equation of a quadratic graph which goes thus; ax²+bx +c = 0, in which case, the determinant is given by the expression; b² - 4ac.

We can consequently evaluate the determinant of the quadratic equation in discuss as follows;

Determinant = b² -4ac = (-5)² - (4×1×3) = 25 - 12

Hence, the determinant in this case is; 13.

Read more on determinant;

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4 0
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You roll two dice. How many ways can you<br> roll a sum of 8 or a sum of 10?
dezoksy [38]

Answer:

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