Answer:
3960.4 bacteria
Step-by-step explanation:
The formula to solve the above question is given as:
P(t) = Po (2) ^t/k
P(t) = Population after time t = ?
Po = Initial population = 650 bacteria
t = Time in days = 7.3 days
k = doubling time = 2.8 days
P(t) = 650 × (2)^7.3/2.8
P(t) = 650 × 2^2.6071428571
P(t) = 650 × 6.0929582599
P(t) = 3960.4228689 bacteria.
Approximately = 3960.4 bacteria
Therefore, the number of bacteria the researcher will have after 7.3 days if they started with 650 bacteria is 3960.4 bacteria.
Round of the number to the nearest whole number then multiply it by itself.
Answer:
Step-by-step explanation:
The constraints are
The red line represents the function
At 
At 
Two points are 
The blue line represents the function
at
at
Two points are 
The other two constraints are 
, 
. So, the point has to be in the first quadrant
From the graph it can be seen there are two points where the function will be maximum let us check them.
So, the maximum value of the function is .
Free LCM Calculator determines the least common multiple (LCM) between 9 and 21 the smallest integer that is 63 that is divisible by both numbers. Least Common Multiple (LCM) of 9 and 21 is 63.
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Prime Factorization of 21.
3 21
7 7
1
