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3 years ago

Which describes the relationship between Angle 1 and Angle 2?

Mathematics

2 answers:

Andrej [43]3 years ago

8 0

Answer:

angles 1 and 2 are supplementary

AveGali [126]3 years ago

3 0

Answer:

angles 1 and 2 are supplementary

Step-by-step explanation:

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Instructions: Match each equations with correct type of event.

Mazyrski [523]

The question is incomplete. Below you will find the missing contents.

The correct match of events with order are,

P(A)P(B|A) - Dependent event
P(A)+P(B) - Mutually exclusive events
P(A and B)/P(A) - Conditional events
P(A) . P(B) - Independent Events
P(A)+P(B) -P(A and B) - not Mutually exclusive events.

When two events A and B are independent then,

P(A and B)=P(A).P(B)

when A and B are dependent events then,

P(A and B) = P(A) . P(B|A)

When two events A and B are mutually exclusive events then,

P(A and B)=0

So, P(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B)

P(A) + P(B) = P(A or B)

When events are not mutually exclusive then the general relation is,

P(A or B) = P(A) + P(B) - P(A and B)

If the probability of the event B conditioned by A is given by,

$\mathrm{P(B|A)=\frac{P(A~and~B)}{P(A)}}$

Hence the correct match are -

$\mathrm{P(A)P(B|A)\rightarrow}$ Dependent event
$\mathrm{P(A)+P(B)}\rightarrow$ Mutually exclusive events
$\mathrm{\frac{P(A ~and ~B)}{P(A)}\rightarrow}$ Conditional events
$\mathrm{P(A) . P(B)\rightarrow}$ Independent Events
$\mathrm{P(A)+P(B) -P(A ~and ~B)\rightarrow}$ not Mutually exclusive events.

Learn more about Probability of Events here -

brainly.com/question/79654680

#SPJ10

5 0

2 years ago

3x + x- 2x + 8 = 3x + x

Arada [10]

Answer:

x=4

Step-by-step explanation:

3x+x - 2x + 8= 3x + x

4x- 2x +8 = 4x

2x + 8= 4x

8= 2x

x=4

5 0

3 years ago

A single number between 0 and 9 occurring either alone or in a larger number is called a what

USPshnik [31]

Answer:

A chronilagical corientation

Step-by-step explanation:

My teacher told me :()()()

6 0

3 years ago

Can someone please help me

Contact [7]

slope = (6 - 1)/(-2 - 1) = 5/-3 = -5/3

Equation

y - 6 = -5/3 (x + 2)

Hope it helps

6 0

3 years ago

Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).

Arisa [49]

The distance between a point $(x,y,z)$ on the given plane and the point (0, 2, 4) is

$\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}$

but since $\sqrt{f(x,y,z)}$ and $f(x,y,z)$ share critical points, we can instead consider the problem of optimizing $f(x,y,z)$ subject to $x-2y+3z=6$ .

The Lagrangian is

$L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)$

with partial derivatives (set equal to 0)

$L_x=2x+\lambda=0\implies x=-\dfrac\lambda2$
$L_y=2(y-2)-2\lambda=0\implies y=2+\lambda$
$L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2$
$L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6$

Solve for $\lambda$ :

$x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6$
$\implies2=7\lambda\implies\lambda=\dfrac27$

which gives the critical point

$x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7$

We can confirm that this is a minimum by checking the Hessian matrix of $f(x,y,z)$ :

$\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}$

$\mathbf H$ is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

$\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}$

8 0

3 years ago