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2 years ago

What is 25/99 simplified

Mathematics

2 answers:

pantera1 [17]2 years ago

7 0

Answer:

It cannot be simplified

Step-by-step explanation:

25 does not go into 99, and neither share common denominators.

astra-53 [7]2 years ago

4 0

Answer:

i dont think you can simplify it any more

Step-by-step explanation:

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Alma and Crystal went out to et and spent $16. They wanted to tip the waitress 15%, what was the total cost of their meal includ

Licemer1 [7]

Answer:

B: $18.40

Step-by-step explanation:

100% is equal to $16 so 5% would be 16/20 or $0.80 then to get 15% you would multiply $0.80 by 3 which is $2.40. This is the tip. Then do $16 + $2.40 and the total + tip is $18.40. (Double check to make sure I'm correct)

8 0

2 years ago

Read 2 more answers

The 2 in the middle is the one that I needed help <br> Please

r-ruslan [8.4K]

Answer:

The equation is p=34a+12, and a=7

Step-by-step explanation:

Perimeter is all of the sides added together

p=12a+6a+8+6a+8+10a-4

Combine like-terms

p=34a+12

Solve for a by making p equal to 250

250=34a+12

Subtract 12 from both sides

238=34a

Divide both sides by 34

7=a

4 0

3 years ago

In this diagram, what is the value of b, correct to the nearest tenth?

lilavasa [31]

We will use the Sine Law:
$\frac{sin 54.33}{b}= \frac{sin29.16}{3} \\ b = \frac{3sin54.33}{sin29.16}$
b = 5.001
Answer: D) 5.0

3 0

3 years ago

The nth term of a sequence is n^2 + 20.

Olegator [25]

Answer:

$\large\boxed{a)\ 21,\ 24,\ 29}\\\boxed{b)\ \text{five terms}}$

Step-by-step explanation:

$a_n=n^2+20\\\\a)\\\\\text{Substitute}\ n=1,\ n=2\ \text{and}\ n=3\ \text{to the }\ a_n:\\\\a_1=1^2+20=1+20=21\\\\a_2=2^2+20=4+20=24\\\\a_3=3^2+20=9+20=29$

$b)\\\\\text{You have to solve the inequality:}\\\\n^2+20$

3 0

3 years ago

Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$

Viktor [21]

When $n=0$ , we have

$5^{3^0} + 1 = 5^1 + 1 = 6$

$3^{0 + 1} = 3^1 = 3$

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for $n=k$ , that

$3^{k + 1} \mid 5^{3^k} + 1$

Now for $n=k+1$ , we have

$5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)$