Distribute the five to [3q-10]
Combine like terms [15q] and [-5q]
Add 50 on each side
Divide by 10 on each side
Simplify
<h3>
Answer: 1/6</h3>
Work Shown:
x = 0.1666666...
10x = 1.666666...
100x = 16.666666...
100x - 10x = 16.666666... - 1.666666...
90x = 15
x = 15/90
x = (1*15)/(6*15)
x = 1/6
So, 1/6 = 0.1666666...
The first car consumed 40 gallons of gas and second car consumed 30 gallons of gas
<em><u>Solution:</u></em>
Let x = gallons consumed by car 1
Let y = gallons consumed by car 2
Fuel efficiency of car 1 = 15 miles per gallon
Distance covered in 1 gallon of gas = 15 miles
Fuel efficiency of car 2 = 25 miles per gallon
Distance covered in 1 gallon of gas = 25 miles
<em><u>Given a total gas consumption of 70 gallons</u></em>
Therefore,
gallons consumed by car 1 + gallons consumed by car 2 = 70
x + y = 70 ------ eqn 1
<em><u>The two cars went a combined total of 1350 miles</u></em>
Therefore,
gallons consumed by car 1 x distance covered in 1 gallon of gas of car 1 + gallons consumed by car 2 x distance covered in 1 gallon of gas of car 2 = 1350

15x + 25y = 1350 ----- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
x = 70 - y ------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
15(70 - y) + 25y = 1350
1050 - 15y + 25y = 1350
10y = 1350 - 1050
10y = 300
y = 30
<em><u>Substitute y = 30 in eqn 3</u></em>
x = 70 - 30
x = 40
Thus first car consumed 40 gallons of gas and second car consumed 30 gallons of gas
Answer:
y=7
Step-by-step explanation:
To calculate the standard equation of a line given two points, you need to calculate the slope and the y intercept.
The slope is the change in y variables over the change in x variables between two points.
(7-7)/(4-0)
that gives you a slope of 0, ie the line is horizontal. That means that the y value is going to be constant while the x value changes, so you can write the equation as y= y value in any point, so y=7.