Concentric circles because if a line is tangent to one circle, it would only intersect teh other
Answer:
- KEi = 2.256×10^5 J
- KEf = 9.023×10^5 J
- 4 times as much work
Step-by-step explanation:
The kinetic energy for a given mass and velocity is ...
KE = (1/2)mv^2 . . . . . m is mass
At its initial speed, the kinetic energy of the car is ...
KEi = (1/2)(810 kg)(23.6 m/s)^2 ≈ 2.256×10^5 J . . . . . m is meters
At its final speed, the kinetic energy of the car is ...
KEf = (1/2)(810 kg)(47.2 m/s)^2 ≈ 9.023×10^5 J
The ratio of final to initial kinetic energy is ...
(9.023×10^5)/(2.256×10^5) = 4
4 times as much work must be done to stop the car.
_____
You know this without computing the kinetic energy. KE is proportional to the square of speed, so when the speed doubles, the KE is multiplied by 2^2 = 4.
Answer:
1/25
Step-by-step explanation:
5^-2
We know that a^ -b = 1/ a^b
5^-2 = 1/ 5^2
= 1/25
The answer will be 4.9. =)
Since we know 1 metre is 0.01 dekametres, we can use this to answer the question!
We simply multiply 490 by 0.01. =)
Answer:
Step-by-step explanation:
A(x)=3x^2
B(x)=8x+3
A(x)=B(x)
3x^2=8x+3
3x^2-8x-3=0
factor
(3x+1)(x-3)=0
x-3=0
x=3
3(3^2)=8(3)+3
3(9)=24+3
27=27
