Answer:
0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
Step-by-step explanation:
Given the data in the question;
sample size n = 28
slope of the least squares regression line of y on x or sample estimate = 0.0623
standard error = 0.0224
95% confidence interval
level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05
degree of freedom df = n - 2 = 28 - 2 = 26
∴ the equation will be;
⇒ sample estimate ± ( t-test) ( standard error )
⇒ sample estimate ± (
) ( standard error )
⇒ sample estimate ± (
) ( standard error )
⇒ sample estimate ± (
) ( standard error )
{ from t table; (
) = 2.055529 = 2.056
so we substitute
⇒ 0.0623 ± ( 2.056 )( 0.0224 )
Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
Answer:
93.4 g/mL x 20. mL = 1868g.
489.7m / 53.061 s = 9.23 m/s
216.3 m/66.4 s = 3.26 m/s.
Step-by-step explanation:
Let's analyze each case.
93.4 g/mL x 20. mL
Hewe we are multiplying g/ml*ml. So we have the answer is (g*ml/ml) = g.
So
93.4 g/mL x 20. mL = 1868g.
489.7m / 53.061 s
We are dividing a measurement in m by a measurement in s. So the answer is in m/s.
So
489.7m / 53.061 s = 9.23 m/s
216.3 m/66.4 s
Same as above.
We are dividing a measurement in m by a measurement in s. So the answer is in m/s.
So
216.3 m/66.4 s = 3.26 m/s.
Answer:
9 is the right answer
Step-by-step explanation:
I. If c = - 4 and d = 10
then
= 
= 
= 9
Hope that help :D
Set the two values equal to each other with 18x-2=12x+2 and then plug it in to the equation and solve