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3 years ago

Josie had a choice of 3 breads, 4 choices of meat, and 4 choices of cheeses to make a sandwich.

Mathematics

2 answers:

tatyana61 [14]3 years ago

4 0

3*4*4=48
she can make 48 different sandwiches

dedylja [7]3 years ago

4 0

Answer:

The answer is 48

Step-by-step explanation:

For every different sandwich, she needs to choose one breat, one meat and one cheese.

For each choice of bread, there are 4 choices of meat and 4 choices of cheese. Also, for each meat, there are four choices of cheese. It means that for each bread there are 4(choices of meat)*4(choices of cheeses) = 16 possible combinations.

There are also 3 choices of breads. For each bread, there are 16 possible combinations. So, in all, there are 3*16 = 48 possible combinations.

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3 years ago

The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

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Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. Favorable cases for Both the laptops to be selected = $_2C_2$ = 1

Total number of cases = 15

Required probability is $\frac{1}{15}$ .

b. Favorable cases for both the desktop machines selected = $_4C_2=6$

Total number of cases = 15

Required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

2. Both desktop:

Favorable cases = $_4C_2=6$

Total number of favorable cases = 8 + 6 = 14

Required probability is $\frac{14}{15}$ .

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3 years ago

Sandra has developed a program designed to increase reading comprehension scores in 6th graders. She randomly selects three stud

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Step-by-step explanation:

From the information given in the question, we are informed that Sandra developed a program that was designed to increase reading comprehension scores in 6th graders and she then randomly selects three students and has them participate in her program.

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