Let us use the formula with the point (4,5) and (0,2)
![\begin{gathered} d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}=\sqrt[]{(4-0)^2+(5-2)^2} \\ =\sqrt[]{16+9}=\sqrt[]{25}=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d%3D%5Csqrt%5B%5D%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D%3D%5Csqrt%5B%5D%7B%284-0%29%5E2%2B%285-2%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B16%2B9%7D%3D%5Csqrt%5B%5D%7B25%7D%3D5%20%5Cend%7Bgathered%7D)
Answer:
Simplify the denominator.
Tap for more steps...
x
(
x
+
3
)
(
x
−
3
)
⋅
3
x
x
2
−
5
x
+
6
Factor
x
2
−
5
x
+
6
using the AC method.
Tap for more steps...
x
(
x
+
3
)
(
x
−
3
)
⋅
3
x
(
x
−
3
)
(
x
−
2
)
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
(
x
+
3
)
(
x
−
3
)
,
(
x
−
3
)
(
x
−
2
)
The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
The number
1
is not a prime number because it only has one positive factor, which is itself.
Not prime
The LCM of
1
,
1
is the result of multiplying all prime factors the greatest number of times they occur in either number.
1
The factor for
x
+
3
is
x
+
3
itself.
(
x
+
3
)
=
x
+
3
(
x
+
3
)
occurs
1
time.
The factor for
x
−
3
is
x
−
3
itself.
(
x
−
3
)
=
x
−
3
(
x
−
3
)
occurs
1
time.
The factor for
x
−
2
is
x
−
2
itself.
(
x
−
2
)
=
x
−
2
(
x
−
2
)
occurs
1
time.
The LCM of
x
+
3
,
x
−
3
,
x
−
3
,
x
−
2
is the result of multiplying all factors the greatest number of times they occur in either term.
(
x
+
3
)
(
x
−
3
)
(
x
−
2
)
Step-by-step explanation:
there does that help
Answer:
60
Step-by-step explanation:
-2(20-50)
-40 + 100 = 60
Answer:
8 pieces of candy
Step-by-step explanation:
Take the original amount of candy in the bowl to be 
.
It says that 20 pieces of candy were added, therefore there are 
pieces of candy in the bowl.
Half of the candy is gone, therefore 
pieces of candy are left in the bowl.
After half of the candy is gone, there are 14 pieces left, so we can say that 
Solve for :
