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mrs_skeptik [129]
4 years ago
14

javier rode his bike for a total of 41 minutes. before lunch he rode 1 minute less than 5 times the number of minutes he rode af

ter lunch. how many times did Javier ride before lunch?
Mathematics
1 answer:
notka56 [123]4 years ago
8 0

Answer:

Javier rode bike 34 minutes before lunch.


Step-by-step explanation:


Let the number of minutes Javier rode the bike after lunch be = x minutes


Then according to question number of minutes he rode the bike after lunch

= 5x-1


Total number of minutes he rode bike = 41 min

Therefore,

x+5x-1 =41


On solving


6x= 41+1 =42


Divide both side by 6 we get

x= 7


Number of minutes he ride before lunch

= 5(7)-1 = 35-1=34 min


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Answer:

a = $80.3

b = $80

c = 4

d = 16

e = 4

f = 88

g = $132

h = 33%

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Step-by-step Explanation:

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==>a ($80.3) rounded to the nearest 10 to find b = $80

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Thus, 80 = 2⁴ * 5

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d = 16

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e = ²/8 × 16

e = 2 × 2

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f = 0.04 × 2200

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If £1 = $1.5,

£88 = $g

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==> Converting \frac{g}{400} into % = h%

h = 132÷400 ×100

h = 0.33 × 100

h = 33%

==> √(h + 3) = i

i = √(33 + 3)

i = √36

i = 6

==> i × (3 + 2) = j

j = 6 × (3 + 2)

j = 6 × 5

j = 30

==> j% of 70 = k

k = j% × 70

k = 30% × 70

k = 0.3 × 70

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⅖ × $90 = m

m = 0.4 × 90

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==> √m + m = n

n = √36 + 36

n = 6 + 36

n = 42

==>Converting n% to fraction = o

Thus, o = 42/100

o = 21/50

==> o of 250 = p

p = 21/50 × 250

p = (21 × 250)/50

p = 21 × 5

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==> expressing p as a product of its primes i.e. p = 3 × 5 × q

105 = 3 × 5 × 7

Therefore, q = 7

==> Given a rectangle with dimensions of q cm and r cm, with an area of 56cm². Let's find r.

Area of rectangle = length × width = q × r

Area = 56 cm²

q = 7 cm

r = ?

56 = 7 × r

56/7 = r

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r = 8 cm

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s = 8 × 0.3

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t = 2.4 ÷ 0.6

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1 × u = 100 × 4

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==> Vikki (v) and John shares $u in the ratio 7:3. Thus, Vikki (v) would receive the following:

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