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2 years ago

Which triangle has hypotenuse AE

Mathematics

2 answers:

Lesechka [4]2 years ago

7 0

Answer:

HAE

Step-by-step explanation:

Vinvika [58]2 years ago

6 0

Your answer is............Triangle BAE

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serious [3.7K]

Download the app photomath it will help you

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2 years ago

On a day, a video was posted online, 5 people watched the video. The next day the number of viewers had doubled. This tend conti

OleMash [197]

Answer:

128 ×5=640 so 128 people so after 4weeks

7 0

3 years ago

Jack is playing a game. When a player wins 3 consecutive games, the player receives 10 bonus points and then the player’s total

Paladinen [302]

The function can be described as

b(p)= player receives 10 bonus points
b(p)= p+10

s(p)= increases 5% of the player’s current points
s(p)= p*(100%+5%)= p*1.05

then (s ∘ b)(p) would be
s(p)= p*1.05
(s ∘ b)(p)= (p+10)*1.05
(s ∘ b)(p)= 1.05p+10.5

4 0

3 years ago

Four times a number added to 7 times the number equals 44.

zysi [14]

If you're looking for the value of the number, then here's how:
Let's call the number x
4x + 7x = 44
11x = 44
÷ 11
x = 4
So the number you're looking for is 4, if you wanted to know something else then let me know!

8 0

3 years ago

I guess I'm lacking in differential equations. I couldn't solve this question. Can you help me?

Sonja [21]

Answer:

See Explanation.

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Reciprocals

Algebra II

Log/Ln Property: $ln(\frac{a}{b} ) = ln(a) - ln(b)$

Calculus

Derivatives

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Derivative of Ln: $\frac{d}{dx} [ln(u)] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

$ln(\frac{2x-1}{x-1} )=t$

Step 2: Differentiate

Rewrite: $t = ln(\frac{2x-1}{x-1})$
Rewrite [Ln Properties]: $t = ln(2x-1) - ln(x - 1)$
Differentiate [Ln/Chain Rule/Basic Power Rule]: $\frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1$
Simplify: $\frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}$
Rewrite: $\frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}$
Combine: $\frac{dt}{dx} = \frac{-1}{(2x-1)(x-1)}$
Reciprocate: $\frac{dx}{dt} = -(2x-1)(x-1)$
Distribute: $\frac{dx}{dt} = (1-2x)(x-1)$

8 0

3 years ago

Read 2 more answers