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3 years ago

What is the answer to 7f/11 =7/11

Mathematics

2 answers:

Talja [164]3 years ago

6 0

7f/11=7/11

Cross-multiply.

(7f)/11=7/11

7f*(11)=(7)*(11)

77f=77

Divide both sides by 77.

77f/77=77/77

f=1

serious [3.7K]3 years ago

5 0

So,

$\frac{7f}{11} = \frac{7}{11}$

Multiply both sides by 11.
$7f = 7$

Divide both sides by 7.
f = 1

Check.
$\frac{7(1)}{11} = \frac{7}{11}$
$\frac{7}{11} = \frac{7}{11}$ This checks.

S = {1}

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5-2(3z+2)=-4(1-2z) please help lol

Sveta_85 [38]

Answer:

z= 5/14

Step-by-step explanation:

Let's solve your equation step-by-step.

5−2(3z+2)=−4(1−2z)

Step 1: Simplify both sides of the equation.

5−2(3z+2)=−4(1−2z)

5+(−2)(3z)+(−2)(2)=(−4)(1)+(−4)(−2z)(Distribute)

5+−6z+−4=−4+8z

(−6z)+(5+−4)=8z−4(Combine Like Terms)

−6z+1=8z−4

Step 2: Subtract 8z from both sides.

−6z+1−8z=8z−4−8z

−14z+1=−4

Step 3: Subtract 1 from both sides.

−14z+1−1=−4−1

−14z=−5

Step 4: Divide both sides by -14.

−14z/ = -5

−14 -14

=5/14

z= 5/14

3 0

3 years ago

The ratio of the diameters is 15:11. If the diameter of the smaller ball is 55cm, what is the volume of the larger ball? Round t

gizmo_the_mogwai [7]

Answer:

220,781.25 cubic cm

Step-by-step explanation:

Given ratio of the diameters = 15:11

Let the actual value of of diameters be 15x and 11x to maintain the ratio of 15:11

Given that smaller one has diameter of 55cm

thus 11x = 55cm

x = 55/11 cm = 5

Thus, diameter of larger ball = 15xcm= 15*5cm =75cm.

we know that radius is half of diameter

Radius = diameter/2

Thus radius of larger ball = 75/2 cm = 37.5 cm.

Volume of sphere is given by $(4/3)\pi r^3$

we know that ball has spherical shape

thus volume of larger ball is calculated as given below

$volume \ of \ ball = (4/3)\pi r^3\\=> volume \ of \ ball = (4/3)*3.14* 37.5^3\\=> volume \ of \ ball = (4/3)*3.14* 37.5^3\\=> volume \ of \ ball = 220,781.25$