Well the answer would be 120=120 and 68=68
The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417
Answer:
x = -5
Step-by-step explanation:
Answer:
y = -2x + 5
Step-by-step explanation:
y=
-3
Slope of this line m₁ = 1/2
Slope of the line perpendicular to this line = m₂
m₁ *m₂ = -1
m₂ = -1 *2/1 = -2
Slope = -2; (1,3)
y- y₁ = m(x-x₁)
y - 3 = -2(x - 1)
y - 3 = -2x + 2
y = -2x +2 +3
y = -2x + 5
the answers are clear if you use priority and equation rules.
- q=11
- u=2
- a=13
- l=8
- s=12