A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed
of 1.3 m/s, how fast is the length of his shadow on the building decreasing when he is 4 m from the building
1 answer:
Answer:
The length of shadow decrease at 0.48 m/s.
Step-by-step explanation:
The distance of man from building = x
Thus initially, x = 12
It is given that dx/dt= -1.3 m/s
Let the shadow height = Y
Now solve for the
when x=4
from the diagram (triangle) it can be seen similar triangles with similar base/height ratios.

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