Question

What is the equation of the line that passes through the point (-4,-3) and has a slope of 5

Answer 1

Answer:

(d) y = 5x + 17

Step-by-step explanation:

Coordinate = (-4, -3)

Slope = 5

y = 5x + b

-3 = 5(-4) + b

-3 = -20 + b

b = 17

y = 5x + 17

Answer 2

Answer:

d) y=5x+17

Step-by-step explanation:

Hello , I think  I can help you with this

if you have the slope and a point of a line, it is possible to find the equation using

$y-y_{0} =m(x-x_{0})$

where:

$(x_{0},y_{0} )$

are the coordinates of the known point , and m is the slope

Step 1

Let

m=5

P(-4,-3)

put the values into the equation

$y-y_{0} =m(x-x_{0})\\y-(-3)=5(x-(-4))\\y+3=5x+20\\Now,\ solve\ for\ y\ to\ obtain\ the\ equation\\subtract\ 3\ in\ both\ sides\\y+3-3=5x+20-3\\y=5x+17$

y=5x+17⇒d.)

Have a nice day.