Question

Write the equation of a line that is parallel to y=0.6x + 3 and that passes through the point (-3,-5)

Answer 1

Answer:

$\large\boxed{y=0.6x-3.2}$

Step-by-step explanation:

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

We have

$y=0.6x+3$

Parallel lines have the same slope. Therefore we have the equation:

$y=0.6x+b$

The line passes through the point (-3, -5). Put the coordinates of the point to the equation and solve it for b:

$-5=0.6(-3)+b$

$-5=-1.8+b$            add 1.8 to both sides

$-3.2=b$

Finally we have:

$y=0.6x-3.2$