This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
11/12 + 1 3/4=
1 3/4 = 7/4 = 21/12
11/12 + 21/12 = 32/12 = 2 8/12 = 2 2/3 oz
Answer:
12 rolls
Step-by-step explanation:
2 dozen is 24 so if he used a dozen which is 12 then he would have 12 left
Answer:
Calico Crayfish has the largest range ⇒ The range = 9
Step-by-step explanation:
∵ The rang is the difference between the largest value
and the smallest value
In the Calico Crayfish the largest value is 10 and the smallest value is 1
∴ The range = 10 - 1 = 9
In the Zebra Mussel the largest value is 10 and the smallest value is 2
∴ The range = 10 - 2 = 8
In the Blue-back Herring the largest value is 10 and the smallest value is 4
∴ The range = 10 - 4 = 6
In the Shield Darter the largest value is 9 and the smallest value is 2
∴ The range = 9 - 2 = 7
∴ The largest range is 9 in Calico Crayfish
