I must confess that I was about to pass this question by, but I was captured by the respectful and dignified way in which you asked for help.
A careful reading of the problem gives you two equations in two unknowns, which you can then solve as simultaneous equations. Here's how it looks:
Call 'C' the price of the senior <u>C</u>itizen ticket.
Call 'S' the price of the <u>S</u>tudent ticket.
On the first night . . . 10 C + 12 S = 208
On the second night . . . 8C + 3 S = 74
Those are your two simultaneous equations. Now the idea is to multiply or divide each side of one equation in such a way that when you add or subtract it from the other equation, one of the variables will become a zero quantity ... you'll be left with an equation in one variable, which you can easily solve. THEN, knowing the value of one variable, you can put it back into one of the original equations,and find the value of the other variable.
This all sounds more complicated than it is. Here's how it goes:
We have . . .
10 C + 12 S = 208 and
8C + 3 S = 74
I'm going to multiply each side of the second equation by 4, and then write it under the first one:
10 C + 12 S = 208
32 C + 12 S = 296
Now, subtract the lower equation from the upper one, and you get . . .
- 22 C + 0 = - 88
Divide each side of this one by -22 and you have <em>C = $4.00</em> .
THAT's what you need, to blow the whole problem wide open. Knowing
the value of 'C', let's substitute it into the equation for the first night:
10 C + 12 S = 208
10(4) + 12 S = 208
40 + 12 S = 208
Subtract 40 from each side : 12 S = 168
Divide each side by 12 : <em>S =</em><em> $ 14.00 </em>.
Finally, as we look over our results, and see that Students have to pay $14 to see the show but Seniors can get in for only $4 , we reflect on this ... or at least I do ... and realize that getting old is not necessarily all bad.
Answer:
The sum of the roots is 0.5
Step-by-step explanation:
<u><em>The correct question is</em></u>
What is the sum of the roots of 20x^2-10x-30
we know that
In a quadratic equation of the form
The sum of the roots is equal to
in this problem we have
so

substitute
<u><em>Verify</em></u>
Find the roots of the quadratic equation
The formula to solve a quadratic equation is equal to


substitute





The roots are x=-1 and x=1.5
The sum of the roots are
----> is ok
9514 1404 393
Answer:
(a) 26 units
Step-by-step explanation:
The left-side vertical line extends from y = -3 to y = +3, so is 3-(-3) = 6 units long.
The bottom side horizontal line extends from x = -5 to x = 2, so is 2 -(-5) - 7 units long.
The sum of these two sides is 6 + 7 = 13 units. These two sides make up half of the perimeter, which is the total length of all four sides.
The perimeter is 2 × 13 units = 26 units.
0.1 decrease in 15 minutes
unit rate is 0.1 / 15 = 0.00667
Temperature is decreasing by 0.00667 degrees Celsius per minute
We want to change the digit in the number 5,341 into 5,841, and to find the difference between the numbers.
Refer to the figure shown below.
The number 3 is in the 3rd place (hundreds) of the number 5,341 as a digit.
It is replaced by 8 to form the number 5,841.
This means that 300 is replaced by 800 because, in the third place, we count by hundreds in the 3rd place.
The difference between 800 and 300 is 500.
Subtraction of 5,341 from 5,841 also yields 500.
Answer:
The digit is in the 3rd place (hundreds).
The difference between the numbers is 500.