Answer:
Step-by-step explanation:
Given :
Two points are given in graph (-6, -4) and {7, 5).
The point-slope form of the equation of a straight line is:
------------(1)
Let and
The slope of the line
Put all known value in above equation.
The slope of the line
We know m, and also know that , so we put these value in equation 1.
Therefore, the equation of the line is .
The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.
<h3>What is the first-order condition in differential calculus?</h3>A first-order differential equation is represented by the equation with 2 variables x & y, including its function f(x,y) specified on a xy-plane.
Given that:
Let us first differentiate the above equation with respect to x, we have:
(multiply by -1)
44x - 22y = 110 ------ (equation 1)
Now, differentiating with respect to y, we have:
22x - 22y = 40 ----- (equation 2)
Now, we have a system of equations:
44x - 22y = 110
- ---- ( subtracting equation 2 from 1; elimination method)
<u> 22x - 22y = 40 </u>
<u>22x + 0 = 70 </u>
<u />
x = 70/22
Replacing the value of x into equation (1), we have:
44x - 22y = 110
44(70/22) - 22y = 110
140 - 22y = 110
140 - 110 = 22y
30 = 22y
y = 30/22
Learn more about the first-order conditions in differential calculus here;
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