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MaRussiya [10]
3 years ago
15

Help me with both or just one

Mathematics
2 answers:
lys-0071 [83]3 years ago
8 0
12.
Let's set up an equation using w to represent the weekly allowance.
w/2 + 10 = 18
Then solve:
Subtract 10 from both sides
w/2 = 8
Multiply by two on both sides
w = 16
The answer is 16.

13.
Let's set up another equation using c to represent the original number of candy.
(c - 3) ÷ 5 = 3
Solve:
Multiply by 5 on both sides
c - 3 = 15
Add three on both sides
c = 18
The answer is 18

Hope this helped! If you have any more questions or don't understand, please comment or DM me. :)
nexus9112 [7]3 years ago
7 0
Im pretty sure the first one would be 16 dollars
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Step-by-step explanation:

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3 years ago
Read 2 more answers
You open a drink stand where you sell coffee and hot chocolate. You sell coffee for $1.80 and hot chocolate for $3.15. At the en
Usimov [2.4K]

Answer:

c = 69 and h = 51

Step-by-step explanation:

You will need two different equations here

use variable c as coffee and variable h as hot chocolate

c + h = 120

1.80c + 3.15h = 284.40

By moving variables, you can alter the first equation

h = 120 - c

Now insert this into the second equation

1.80c + 3.15(120 - c) = 284.40

Multiply

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Subtract the c

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Subtract 378 from both sides

-1.35c = -93.6

Divide both sides by -1.35

c = 69

Then plug into the first equation

69 + h = 120

Subtract 69

h = 51

7 0
3 years ago
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